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djyliett [7]
3 years ago
13

For which segment lengths is AC¯¯¯¯¯ parallel to DE¯¯¯¯¯ ?

Mathematics
2 answers:
Lemur [1.5K]3 years ago
8 0

I just took the test, this is the only question i got wrong.

#1-Parallel.

#2-Parallel

#3-Not parallel


Kruka [31]3 years ago
4 0

Answer:


Step-by-step explanation:

By triangle theorem for similarity we have

AC||DE if and only if

the ratios

\frac{AD}{BD}=\frac{CE}{EB}

Option I:

Here we find the ratios are equal to 1/2

Hence parallel

OPtion 2:

Here we get both ratios equal to 2/3 Hence parallel

Option 3:

Here we get I ratio =2/5 and II ratio =4/7

Since the two are not equal we get not parallel

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Answer:

Point form: (4, 4)

x = 4, y = 4

7 0
3 years ago
Please help with this!!!
iris [78.8K]

Answer: The y values remain the same, but the x value changes its sign

Step-by-step explanation: There is a way to remember this. If you reflect across the y axis the y will stay the same and, if you reflect across the x axis the x will stay the same. So if the axis is in the problem then that axis will stay the same and the other axis will change to its opposite.

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Z1 and Z2 are vertical angles. Z2 has a measure of 63º. What is the measure of Z1? Enter your answer in the box.​
Sergio039 [100]

Answer:

vertical angles are equal:

< (1) = < (2) (in fact they are congruent angles)

so, if measure of < 1 is 63° and measure of < 2 is 4x-9°, than

4x-9=63° ...solve for x

4x=63%2B9°

4x=72°

x=72%2F4°

x=18°

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Step-by-step explanation:

Hope it helps

7 0
2 years ago
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olga_2 [115]

Answer:

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simple interest=principle*rate*time/100

simple interest=20000*5.6*3/100

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3 0
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Therefore, x-intercept of f'(x) = 0 is somewhere between the two x-intercepts, ranging from -8 to 0.

7 0
3 years ago
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