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2 years ago

How would 0.333333 be classified?

1 answer:

3 0

Depends what you mean by that question. If you mean other forms, it would be:

33%, 33/100.

If you want the name for the 0.3 occuring, it would be irrational.

Please make this answer the brainiest!

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What do people mean when they say “An eye for an eye will make the whole world blind”

Scorpion4ik [409]

Answer:

i think it means karma

Step-by-step explanation:

when you do something bad, later on down the road something bad will happen to you.

6 0

2 years ago

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Answer please You feeling lucky punk

Ksivusya [100]

Answer:

Final velocity is 3

Change in velocity is 4

Initial velocity is 2

Instantaneous velocity is 1

Acceleration is 5

7 0

2 years ago

A group of 5 families at Baileys Middle School sold magazine subscriptions to raise money for the school. $6.00, $7.00, $4.00,

mash [69]

Answer:

The median amount of money raised is $5.00

Step-by-step explanation:

To find the median amount of money raised, we will follow the steps below:

First, arrange the data giving in ascending order. That is

$6.00, $7.00, $4.00, $5.00, $3.00

We will arrange it in ascending order, hence

$3.00, $4.00, $5.00, $6.00, $7.00

The median is the middle number, we will now proceed to take the middle number.

The middle number is $5.00

Therefore, the median amount of money raised is $5.00

6 0

3 years ago

Find the general solution of the differential equation and check the result by differentiation. (Use C for the constant of integ

atroni [7]

Answer: $y=Ce^(^3^t^{^9}^)$

Step-by-step explanation:

Beginning with the first differential equation:

$\frac{dy}{dt} =27t^8y$

This differential equation is denoted as a separable differential equation due to us having the ability to separate the variables. Divide both sides by 'y' to get:

$\frac{1}{y} \frac{dy}{dt} =27t^8$

Multiply both sides by 'dt' to get:

$\frac{1}{y}dy =27t^8dt$

Integrate both sides. Both sides will produce an integration constant, but I will merge them together into a single integration constant on the right side:

$\int\limits {\frac{1}{y} } \, dy=\int\limits {27t^8} \, dt$

$ln(y)=27(\frac{1}{9} t^9)+C$

$ln(y)=3t^9+C$

We want to cancel the natural log in order to isolate our function 'y'. We can do this by using 'e' since it is the inverse of the natural log:

$e^l^n^(^y^)=e^(^3^t^{^9} ^+^C^)$

$y=e^(^3^t^{^9} ^+^C^)$

We can take out the 'C' of the exponential using a rule of exponents. Addition in an exponent can be broken up into a product of their bases:

$y=e^(^3^t^{^9}^)e^C$

The term e^C is just another constant, so with impunity, I can absorb everything into a single constant:

$y=Ce^(^3^t^{^9}^)$

To check the answer by differentiation, you require the chain rule. Differentiating an exponential gives back the exponential, but you must multiply by the derivative of the inside. We get:

$\frac{d}{dx} (y)=\frac{d}{dx}(Ce^(^3^t^{^9}^))$

$\frac{dy}{dx} =(Ce^(^3^t^{^9}^))*\frac{d}{dx}(3t^9)$

$\frac{dy}{dx} =(Ce^(^3^t^{^9}^))*27t^8$

Now check if the derivative equals the right side of the original differential equation:

$(Ce^(^3^t^{^9}^))*27t^8=27t^8*y(t)$

$Ce^(^3^t^{^9}^)*27t^8=27t^8*Ce^(^3^t^{^9}^)$

QED

I unfortunately do not have enough room for your second question. It is the exact same type of differential equation as the one solved above. The only difference is the fractional exponent, which would make the problem slightly more involved. If you ask your second question again on a different problem, I'd be glad to help you solve it.

7 0

1 year ago

Find the area of the triangle with the given base and height. b = 3 m and h = 10 1/2 m

svetoff [14.1K]

Statement:

The base of a triangle is 3m and its height is $10 \frac{1}{2}$ m.

To find out:

The area of the triangle.

Solution:

Given, base = 3m, height = $10 \frac{1}{2}$ m
We know,

$\sf \: area \: \: of \: \: a \: \: triangle = \frac{1}{2} \times base \: \times height$

Therefore, the area of the triangle

$\sf = (\frac{1}{2} \times 3 \times 10 \frac{1}{2} ) {m}^{2} \\ \sf = ( \frac{1}{2} \times 3 \times \frac{21}{2} ) {m}^{2} \\ = \sf \frac{63}{4} {m}^{2} \\ = \sf 15\frac{3}{4} {m}^{2}$

Answer:

The area of the triangle is $\sf \: 15 \frac{3}{4} {m}^{2}$

Hope you could understand.

If you have any query, feel free to ask.

5 0

1 year ago

Read 2 more answers