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Shalnov [3]
3 years ago
13

Consider the line y = x – 4. A line parallel to the graph of the line would have a slope of . A line perpendicular to the graph

of the line would have a slope of .
Mathematics
2 answers:
kotykmax [81]3 years ago
4 2

Answer:

A. 1

B. -1.

Step-by-step explanation:

We have been given an equation of a line y=x-4.

A. We know that slope of parallel lines is always equal,

We can see that slope of our given line is 1, therefore the slope of the line parallel to our given line would be 1.

B. We know that the product of slopes of two perpendicular lines is -1.

Let m represent slope of perpendicular to our given line, then:

m\times 1=-1

m=-1

Therefore the slope of the line perpendicular to our given line would be -1.

PSYCHO15rus [73]3 years ago
5 0

Answer:

2/3  and -3/2

Step-by-step explanation:

Sonia
2 years ago
thank you
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We know
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step 1
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m=(y2-y1)/(x2-x1)----------> (-4-1)/(-1-2)--------> m=5/3

step 2
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find the equation in point-slope form
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A) If the 5th term of an A.P. is double the 7th term, show that the sum of the 17 terms zero.​
gayaneshka [121]

Answer:

see explanation

Step-by-step explanation:

The nth term of an AP is

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where a₁ is the first term and d the common difference

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a₁ + 4d = 2(a₁ + 6d) , that is

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The sum of n terms of an AP is

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5 0
2 years ago
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Mrac [35]

Answer:

what's the question???

5 0
3 years ago
Write in standard form: <img src="https://tex.z-dn.net/?f=%28%5Cfrac%7B%5Csqrt%7B2%7D%7D%7B2%7D%20%2B%20%5Cfrac%7B%5Csqrt%7B2%7D
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Answer:

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Step-by-step explanation:

=(\frac{1}{\sqrt{2}}(1+i))^4\\=\frac{1}{4}(1+i)^2(i+i)^2\\=\frac{1}{4}(2i)(2i)\\=i^2\\=-1

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3 years ago
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