Use synthetic division to divide (x^ 3 + x^ 2 – 40x – 4) ÷ (x – 6)
2 answers:
The answer is C.
Hope this helps!!
For this case we must build a quotient that, when multiplied by the divisor, eliminates the terms of the dividend until reaching the remainder.
It must be fulfilled that:
Dividend = Quotient * Divider + Remainder
Looking at the attached image we have that the quotient is given by:
![x ^ 2 + 7x + 2](https://tex.z-dn.net/?f=x%20%5E%202%20%2B%207x%20%2B%202)
Answer:
Option C
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Answer:
A
Step-by-step explanation:
the graph shows It's the 3rd tallest
Answer:
Hi there!
Your answer is:
the number is 68
Step-by-step explanation:
(18-n) /2 = -25
×2
(18-n) = -50
-18
-n = -68
/-1
n= 68
Plug it back in!
(18-68) /2 = -25 ???
-50/2 = -25 ✓✓✓
Hope this helps
![-56 \leqslant -8x](https://tex.z-dn.net/?f=-56%20%20%5Cleqslant%20-8x)
Divide by -8 (change inequality sign direction)
![7 \geqslant x](https://tex.z-dn.net/?f=%207%20%5Cgeqslant%20x)
Response:
![x \leqslant 7](https://tex.z-dn.net/?f=x%20%5Cleqslant%207)
Answer:
probably 8 lol
Step-by-step explanation:
i just did 600/75 sorry if it's wrong
Answer:
The integral
is 0.
Step-by-step explanation:
A parameterization of curve C can be:
X (t) = cost 0 <= t <= pi
Y (t) = sint 0 <= t <= pi
r (t) = costi + sintj
r '(t) = -sinti + costj
![Fds = [-costsin^3t + sintcos^3t] dt](https://tex.z-dn.net/?f=Fds%20%3D%20%5B-costsin%5E3t%20%2B%20sintcos%5E3t%5D%20dt)
The integral
is given by:
![\int _0^{\pi }\left[-costsin^3t + sintcos^3t dt\right]dt](https://tex.z-dn.net/?f=%5Cint%20_0%5E%7B%5Cpi%20%7D%5Cleft%5B-costsin%5E3t%20%2B%20sintcos%5E3t%20dt%5Cright%5Ddt)
![= \int _0^{\pi }-sin ^3tcostdt + \int _0^{\pi }sintcos^3tdt = 0](https://tex.z-dn.net/?f=%3D%20%5Cint%20_0%5E%7B%5Cpi%20%7D-sin%20%5E3tcostdt%20%2B%20%5Cint%20_0%5E%7B%5Cpi%20%7Dsintcos%5E3tdt%20%3D%200)