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Alika [10]
2 years ago
9

Use synthetic division to divide (x^ 3 + x^ 2 – 40x – 4) ÷ (x – 6)

Mathematics
2 answers:
Marina CMI [18]2 years ago
7 0
The answer is C.

Hope this helps!!

mafiozo [28]2 years ago
4 0

For this case we must build a quotient that, when multiplied by the divisor, eliminates the terms of the dividend until reaching the remainder.

It must be fulfilled that:

Dividend = Quotient * Divider + Remainder

Looking at the attached image we have that the quotient is given by:

x ^ 2 + 7x + 2

Answer:

Option C

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Simplify the following expression (6x2 + 8x - 3) - (3x2 - 6)
Vsevolod [243]

Answer:

3x^2 +8x +3

Step-by-step explanation:

(6x^2 + 8x - 3) - (3x^2 - 6)

Distribute the minus sign

(6x^2 + 8x - 3) - 3x^2 + 6

Combine like terms

3x^2 +8x +3

8 0
2 years ago
Please help asap! Worth 15 points
sdas [7]

Answer: the second one

Step-by-step explanation:

3 0
3 years ago
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X= 0 , 1 , or 7<br> Y= -10, 5, or 10<br> Please helppppp will mark Brainliest
vlabodo [156]

Step-by-step explanation:

6 0
3 years ago
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The factored form of a quadratic equation is y=(2x+1)(x-5), and the standard form is y=2x²-9x-5. Which of the following statemen
podryga [215]

x1= -5 x2=0.5 y= -5

the answer is b as the minuses can be interchanged for the x intercepts

Step-by-step explanation:

As you can see as explained in the pictures

7 0
3 years ago
Quadratic Equations<br> How do I solve a quadratic equation?
malfutka [58]
There are different ways to solve a quadratic equation, the main ones that i'm thinking about right now are:
1) factor the equation as a product:
 ex:        x^2+ 4x + 3 =0
             (x+3) (x+1) = 0
              x=-3 and x=-1 are the solutions.
To find (x+p) and (x+q) you have to think that (p+q )have to be equal to the number that is multiplied by x, in my example it was 4 (3+1=4), (p times q) have to be equal to the last number of the quadratic equation, the one that is not multiplied by any x, that in my example is 3 (3 x 1= 3)

2) The other way to solve a quadratic function is by using a formula:
    given: ax^2 +bx +c=0
    x= (-b +/- <span>√(b^2 -</span> 4ac)) / 2a
    
 ex: 3x^2 + 4x -2=0
    x= (-4 +/- √16-4(3)(-2)) / 6= (-4 +/- √16+24)/6= (-4 +/- <span>√40) / 6
now there are 2 possibilities: x= (-4+</span><span>√40) /6
                                                        and
                                              x= (-4 - </span><span>√40) / 6
I hope the examples were clear enough also if i did't get very nice numbers. Look closely to the sings + and -, they are very important</span>
5 0
3 years ago
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