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Scilla [17]
3 years ago
11

Please help me with this

Mathematics
1 answer:
Len [333]3 years ago
3 0

Answer:

60 degrees

Step-by-step explanation:

To first solve this problem, we need to figure out the size of an interior angle for a regular hexagon.

This can be done with the formula :

angle = \frac{(n-2)*180}{n} , with n being the number of sides

A hexagon has 6 sides so here is how we would solve for the interior angle:

\frac{(6-2)*180}{6}=120 , with n= 6 sides

Now that we know that each interior angle in the hexagon is 120 degrees, we can now turn our attention to the rhombus.

The opposite angles of the rhombus are congruent, so the two larger obtuse angles are congruent, and so are the two smaller acute angles.

It is also important to note that a rhombus is a quadrilateral, so all of its interior angles add up to 360 degrees.

Looking at the rhombus, we already know one of the angles because it is shared by the interior angle of the hexagon, so the two larger angles in the rhombus are both 120 degrees.

But what about the smaller angles? All we need to do is subtract the two larger angles form 360 and divide by 2 to find the angle.

\frac{360-2(120)}{2} = 60 , so the smaller angle in the rhombus is 60 degrees.

Now that we know both the interior angle and smaller angle of the rhombus, we can find x.

Together, angle x and the angle adjacent to it makes up an interior angle of the hexagon, so x plus that angle is going to equal to 120 degrees.

All we need to do is solve for x:

x+60=120

x=120-60

x = 60 degrees

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Answer:

The answer is below

Step-by-step explanation:

The z score is used to determine by how many standard deviations the raw score is above or below the mean. The z score is given by:

z=\frac{x-\mu}{\sigma} \\\\for\ a \ sample(n):\\\\z=\frac{x-\mu}{\sigma/\sqrt{n} }\\\\where\ x=raw\ score,\mu=mean, \sigma=standard deviation

Given that n = 49, μ = 260 mg/dL, σ = 35 mg/dL

a) For x < 210:

z=\frac{x-\mu}{\sigma/\sqrt{n} } =\frac{210-260}{35/\sqrt{49} } =-10

From the normal distribution table, P(x < 210) = P(z < -10) = 0.0001

b) For x > 205:

z=\frac{x-\mu}{\sigma/\sqrt{n} } =\frac{205-260}{35/\sqrt{49} } =-11

For x < 215:

z=\frac{x-\mu}{\sigma/\sqrt{n} } =\frac{215-260}{35/\sqrt{49} } =-9

P(205 < x < 215) = P(-11 < z < -9) = P(z < -9) - P(z < -11) = 0.0001 - 0.00001 = 0.00009

c) For x < 200:

z=\frac{x-\mu}{\sigma/\sqrt{n} } =\frac{200-260}{35/\sqrt{49} } =-12

From the normal distribution table, P(x < 200) = P(z < -12) = 0.00001

d) For x > 222:

z=\frac{x-\mu}{\sigma/\sqrt{n} } =\frac{222-260}{35/\sqrt{49} } =-7.6

From the normal distribution table, P(x > 200) = 1 - P(z < -12) = 1 - 0.0001 = 0.9999

7 0
3 years ago
Help me to do 10(b) answer​
antiseptic1488 [7]

Answer:

Step-by-step explanation:

Big circle:

R = radius = diameter ÷2 = 42 ÷ 2 = 21 cm

Area of big circle= πR²

                            =\dfrac{22}{7}*21*21=22*3*21\\\\\\= 1386 \ cm^{2}

Small circle:

Diameter of small circle  = radius of big circle = 21 cm

r = 21/2 = 10.5 cm

Area of small circle = πr²

                                =\dfrac{22}{7}*10.5*10.5 = 22 * 1.5*10.5\\\\\\= 346 .5 \ cm^{2}

Area of shaded region = area of big circle - area of small circle

= 1386 - 346.5

= 1039.5 cm²

                                 

3 0
2 years ago
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THE ANSWER IS C.

PLEASE VOTE BRAINLIEST

Step-by-step explanation:

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3 years ago
What is the equation of the line below?
Licemer1 [7]

Answer:

y = -\frac{2}{3}x + 1

Step-by-step explanation:

The equation of the line shown can be expressed in the slope-intercept formula as y = mx + b

Let's find m = slope, and b = y-intercept.

Using two points on the line, (0, 1) and (1½, 0),

slope (m) = \frac{y_2 - y_1}{x_2 - x_1} = \frac{0 - 1}{\frac{3}{2} - 0} = \frac{-1}{\frac{3}{2}} = - \frac{2}{3}

y-intercept, b is where the line intercepts the y-axis = 1.

To create an equation for the line, substitute m = -⅔, b = 1 in y = mx + b.

✅The equation would be:

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Answer with Step-by-step explanation:

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Where r= Radius of sphere in ft

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b.Substitute t=1

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\frac{dS}{dt}=\frac{-8\pi}{8}(\frac{1}{4}-\frac{1}{15})^2

\frac{dS}{dt}=-0.1056 ft^3/min

6 0
3 years ago
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