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FinnZ [79.3K]
3 years ago
11

A force of 76 N is applied to an area of 490 cm2. Calculate the pressure in N/m2. Give your answer to the nearest integer.

Mathematics
1 answer:
kolezko [41]3 years ago
4 0

Answer:

Given

Hope it helps

Step-by-step explanation:

Pressure is the force per unit perpendicular area over which the force is applied

p=F/A

Where f is force and a is area

So P

= F/A

= 76N / 0.049m2

= (76/0.049) Nm2

= 76000/49

= 1551.02

Or 1551 N/m2

You might be interested in
An art teacher had 2/3 gallon of paint to pour into containers if he poured 1/8
exis [7]
To find your answer do 2/3 divided by 1/8 = 5 1/3 containers.
6 0
3 years ago
In Sakura's garden, for every 5 red flowers, there are 10 yellow flowers. There are 75 total red and yellow flowers. How many re
sweet [91]

Answer: there are 25 red flowers in Sakura's garden.

Step-by-step explanation:

In Sakura's garden, for every 5 red flowers, there are 10 yellow flowers. This means that if there are 10 red flowers, there would be 20 yellow flowers. if there are 20 red flowers, there would be 40 yellow flowers. Therefore, the ratio of red flowers to yellow flowers in the garden is

5/10 = 10/20 £= 20/40 = 1/2 = 1:2

Total ratio = 2 + 1 = 3

If there are 75 total red and yellow flowers, then the total number of red flowers are in Sakura's garden would be

1/3 × 75 = 25

8 0
3 years ago
First make a substitution and then use integration by parts to evaluate the integral. (Use C for the constant of integration.) x
e-lub [12.9K]

Answer:

(\frac{x^{2}-25}{2})ln(5+x)-\frac{x^{2}}{4}+\frac{5x}{2}+C

Step-by-step explanation:

Ok, so we start by setting the integral up. The integral we need to solve is:

\int x ln(5+x)dx

so according to the instructions of the problem, we need to start by using some substitution. The substitution will be done as follows:

U=5+x

du=dx

x=U-5

so when substituting the integral will look like this:

\int (U-5) ln(U)dU

now we can go ahead and integrate by parts, remember the integration by parts formula looks like this:

\int (pq')=pq-\int qp'

so we must define p, q, p' and q':

p=ln U

p'=\frac{1}{U}dU

q=\frac{U^{2}}{2}-5U

q'=U-5

and now we plug these into the formula:

\int (U-5)lnUdU=(\frac{U^{2}}{2}-5U)lnU-\int \frac{\frac{U^{2}}{2}-5U}{U}dU

Which simplifies to:

\int (U-5)lnUdU=(\frac{U^{2}}{2}-5U)lnU-\int (\frac{U}{2}-5)dU

Which solves to:

\int (U-5)lnUdU=(\frac{U^{2}}{2}-5U)lnU-\frac{U^{2}}{4}+5U+C

so we can substitute U back, so we get:

\int xln(x+5)dU=(\frac{(x+5)^{2}}{2}-5(x+5))ln(x+5)-\frac{(x+5)^{2}}{4}+5(x+5)+C

and now we can simplify:

\int xln(x+5)dU=(\frac{x^{2}}{2}+5x+\frac{25}{2}-25-5x)ln(5+x)-\frac{x^{2}+10x+25}{4}+25+5x+C

\int xln(x+5)dU=(\frac{x^{2}-25}{2})ln(5+x)-\frac{x^{2}}{4}-\frac{5x}{2}-\frac{25}{4}+25+5x+C

\int xln(x+5)dU=(\frac{x^{2}-25}{2})ln(5+x)-\frac{x^{2}}{4}+\frac{5x}{2}+C

notice how all the constants were combined into one big constant C.

7 0
3 years ago
Write the expression in simplest form.<br> (11 + 3) – 2(- 4 1 - 1) =<br> NIO
Aleksandr-060686 [28]

Answer:

11+3=14

-41-1=-42

14-2(-42)

-2(-42)

14+84

98

I hope this is good enough:

5 0
3 years ago
Can any one answer this correctly?
MakcuM [25]

Answer:

A

Step-by-step explanation:

The Y-intercept is -3.

The gradient is -3/4 since it goes down 3 every 4 tiles.

7 0
2 years ago
Read 2 more answers
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