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noname [10]
3 years ago
12

Please help me quick :)

Mathematics
2 answers:
krek1111 [17]3 years ago
7 0
It would be an average of about 8.00 (7.99 to be somewhat exact). You get this by dividing the total amount by 200, the dividing that by 363.
Yakvenalex [24]3 years ago
5 0
Your answer would be $29.04
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Solve the formula s=4pi r^2 for r
andrew11 [14]

Answer:

The formula to find the surface area of a sphere is to take the radius of the sphere and square it and multiply that amount by pi and then multiply that by 4. This is written algebraically as S=4πr2, where S is the surface area, r is the radius, and the value of π is 3.14.

7 0
3 years ago
Which if the following is the equation of a line that passes through the points (2,5) and (4,3)
Taya2010 [7]
Hi there!

First, let's find the slope of the two points using the slope formula (y2 - y1 / x2 - x1).

S = 4 - 2 / 3 - 5
S = 2 / -2
S = -1

Next, we'll plug in the slope and a point into point-slope form (y - y1 = s(x - x1)) in order to find an equation. I will show the work using both points, which will result in two different equations.

(2,5)
y - 5 = -1(x - 2)
y - 5 = -x + 2
y = -x + 7

(4,3)
y - 3 = -1(x - 4)
y - 3 = -x + 4
y = -x + 7

The two equations came out the same! Which is completely okay, and happens sometimes. 

Hope this helps!! :)
If there's anything else that you're needing help with, don't be afraid to reach out!


3 0
3 years ago
-3 1/2 - 2 1/3 explained
lakkis [162]
The answer is 5 5/6 simplified to the max.

rewrite the equation with separated parts

-3 1/2 - 2 1/3

-3 - 2 = -5

-1/2 - 1/3? u need to find the LEAST common denominator

-3/6 - 2/6 = -5/6

how did I get 6?

Rewriting input as fractions if necessary:
1/2, 1/3

For the denominators (2, 3) the least common multiple (LCM) is 6.

Therefore, the least common denominator (LCD) is 6.

Now lastly combine them total and its -5 - 5/6 = -5 5/6.


5 0
3 years ago
Read 2 more answers
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Temka [501]

Answer:

Step-by-step explanation:

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3 years ago
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Vesnalui [34]
I'm pretty sure p = 0
8 0
3 years ago
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