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Klio2033 [76]
3 years ago
5

What are the solutions to equation (x - 21)^2 = 25? x= x=

Mathematics
1 answer:
melomori [17]3 years ago
8 0

The answers for these solutions to equation (x - 21)^2 = 25 are

x = 26

x =16

Picture proof

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Very easy problem !!! Will be Marked Brainliest :)
Butoxors [25]

Answer: Yes it is reasonable.

Step-by-step explanation:

If all the numbers are rounded, 79 will be rounded to 80

12 to 10

and 11 to 10

If there are about 80 kids in 3rd grade, and about 20 kids in Mrs. Henry's class (because 10 girls plus 10 boys)

That means that 80-20

about 60 kids are not in Mrs. Henry's class

Hope this helped!

7 0
3 years ago
Read 2 more answers
Given the arithmetic sequence: u(1)= 124, u(2)= 117, u(3)= 110, u(4)=103,...
omeli [17]

We are given

arithmetic sequence: u(1)= 124, u(2)= 117, u(3)= 110, u(4)=103

so, first term is 124

u(1)= 124

now, we can find common difference

d=u(2)-u(1)

d=117-124

d=-7

now, we can find kth term

u(k)=u(1)+(k-1)d

now, we can plug values

and we get

u(k)=124+(k-1)*-7

u(k)=124-7k+7

u(k)=131-7k

u(k) must be negative

so,

u(k)=131-7k

131-7k

now, we can solve for k

7k>131

k>18.714

so, it's closest integer value is

k=19..............Answer


3 0
3 years ago
A triangle has side lengths of (1.3k+3.5m)(1.3k+3.5m) centimeters, (4.1k-1.6n)(4.1k−1.6n) centimeters, and (9.7n+4.4m)(9.7n+4.4m
Scorpion4ik [409]

Answer:

(5.4k+7.9m+8.1n) centimeters

Step-by-step explanation:

Given the side length of a triangle;

S1 = (1.3k+3.5m) cm

S2 = (4.1k-1.6n) cm

S3 = (9.7n+4.4m) cm

Perimeter of the triangle = S1+S2 + S3

Perimeter of the triangle = (1.3k+3.5m) + (4.1k-1.6n) + (9.7n+4.4m)

Collect the like terms;

Perimeter of the triangle = 1.3k+4.1k+3.5m+4.4m-1.6n+9.7n

Perimeter of the triangle = 5.4k+7.9m+8.1n

Hence the expression that represents the perimeter of the triangle is (5.4k+7.9m+8.1n) centimeters

5 0
3 years ago
Which of the following elevations are deeper than -200 feet? Select all that apply.
Serjik [45]
300 feet and 1300 feet
3 0
3 years ago
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A triangle ABC is inscribed in a circle, such that AB is a diameter. What are the measures of angles of this triangle if measure
Katen [24]

Answer:

∠C=90°

∠A=67°

∠B=23°

Step-by-step explanation:

For angle C:

  Thales' Theorem states that an angle inscribed across a circle's diameter is always a right angle.

  Therefore, since AB is the diameter(hypotenuse) then angle C is the right angle. (90°)

For Angle A:

  The measure of arc BC= 134 degrees. We can just use a formula for an inscribed triangle. ∠A = 1/2 (mBC)

  ∠A= (1/2)134

  ∠A= 77°

For angle B:

  All triangle angles all add up to 180. We can just subtract angles A and C from 180°:

  ∠B = 180-(90+67)

  ∠B = 23°

8 0
4 years ago
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