Answer:
e. 27 rho.
Explanation:
The density of an object, assumed constant, is defined as the relationship between the mass and the volume.
If the object is compressed in such a way that the diameter is reduced to 1/3, this means, that the radius will be reduced in the same proportion.
Now, if the mass remains the same (the compression can't change it) , the volume (assumed to be a perfect sphere) will be reduced also:
V₀ = 4/3*π*r³
Vf= 4/3*π*(r/3)³ = 4/3*π*(r³/27) = V₀/27
As the volume is in in the denominator of the expression for density, this means that the new density will be equal to 27 times the original one:
ρ₀ = m/ V₀
ρ₁ = m/ V₁ = m/ (V₀/27) = 27* (m/V₀) = 27*ρ₀
Answer:
2 Newtons
Explanation:
Therefore, your mass would be 1kg and your acceleration would be 2m/s/s
Plug the numbers into the equation:
which will equal
For example if an iron is heated it will get longer and fatter and its density will decrease. This happens because the mass of a rod stays the same but its volume increases....... A few substances behave differently when heated or cooled. Water is one such substance
True. The speed of any object will have faster acceleration, and eventually slow down due to gravity.