The average power is 
Explanation:
First of all, we calculate the work done to accelerate the car; according to the work-energy theorem, the work done is equal to the change in kinetic energy of the car:
where
:
is the final kinetic energy of the car, with
m = 2000 kg is the mass of the car
v = 60 m/s is the final speed of the car
is the initial kinetic energy of the car, with
u = 30 m/s is initial speed of the car
Soolving:
Now we can find the power required for the acceleration, which is given by

where
t = 9 s is the time elapsed
Solving:

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The same braking force does work on these objects to slow them down. The work done is equal to their change in kinetic energy:
FΔx = 0.5mv²
F = force, Δx = distance traveled, m = mass, v = speed
Isolate Δx:
Δx = 0.5mv²/F
Calculate Δx for each object.
Object 1: m = 4.0kg, v = 2.0m/s
Δx = 0.5(4.0)(2.0)²/F = 8/F
Object 2: m = 1.0kg, v = 4.0m/s
Δx = 0.5(1.0)(4.0)²/F = 8/F
The two objects travel the same distance before stopping.
Answer:
3.44 metres
Explanation:
To determine the vector sum of the displacements Δd1 = 2.4 m [32° S of W]; Δd2 = 1.6 m [S]; and Δd3 = 4.9 m [27° S of E], resolve the given parameters into x - component and y - component.
Resolving into x - component
- 2.4cos32 + 4.9cos27 = 2.3306
Resolving into y - component
- 2.4sin32 - 4.9sin27 - 1.6 = - 2.553
The vector sum of the displacement will be
Sqrt( 2.3^2 + 2.6^2) =
Sqrt ( 11.81)
3.44 m
Therefore, the vector sum of the displacements is 3.44 metres
C according to my calculations
Answer:
1.False
2.4 E
Explanation:
1.We have to find the statement is true or false.
We know that
Time constant,
Time constant is inversely proportional to resistance R .It means when R increases then time constant decreases when R decrease then the time constant decreases.
Statement:The larger the value of R ,the longer it takes the circuit to reach its final steady- state value
It is false.
2.Energy stored in inductor,E=
When I'=2I
Then, 
Hence,the new total energy will become 4 E.