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anzhelika [568]
3 years ago
14

Please need help on this

Physics
1 answer:
Vera_Pavlovna [14]3 years ago
4 0

Answer:

i have no idea

Explanation:

it could be B. but i dont belive in myself sooooooooooo.....ehhhh yeah

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False sometimes you get a bad mutation
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A bus starting from rest moves with a uniform acceleration of 0.1 m s -2 for 2 minutes. Find (a) the speed acquired, (b) the dis
KiRa [710]

Answer:

S=720m anf vf=12m/s

Explanation:

acceleration=a=0.1m/s²

time taken=t=2minutes=2×60=120seconds

vi=0m/s

vf=?

distance covered=S=?

by using second equation of motion

S=vit+1/2at²

S=0m/s×120seconds+1/2(0.1m/s²)(120s)²

S=0m/s+1/2×1440m

S=720m

and now we have to find the vf

vf=vi+at

vf=0m/s+(0.1m/s)(120s)

vf=12m/s

i hope it will help you

8 0
3 years ago
What is the momentum of a 5 kg object that has a velocity of 1.2 m/s? 3.8 kg • m/s 4.2 kg • m/s 6.0 kg • m/s 6.2 kg • m/s
Gnesinka [82]

Answer:

Your answer will be 6.0kg•m/s

Explanation:

In the given question all the required details d given. Using these information's a person can easily find the momentum of the object. In the question it is already given that the mass of the object is 5 kg and the velocity at which it is traveling is 1.2 m/s.We know the equation of finding momentum asMomentum = mass * velocity                   = 5 * 1.2                    = 6So the momentum of the object is 6 Newton.

4 0
4 years ago
Read 2 more answers
The ______ and _______ are used to calculate magnitude and direction of a resultant vector.
S_A_V [24]
Here are the correct answers that would complete the given statement above. The vector quantity and the vector arrow are used to calculate magnitude and direction of a resultant vector. Vector quantity has both magnitude and direction, whereas vector arrow represents<span> the magnitude of a quantity and the direction represents the direction of that quantity. </span>Hope this is the answer that you are looking for. 
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3 years ago
Consider the following cyclic process carried out in two steps on a gas. Step 1: 44 J of heat is added to the gas, and 20. J of
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Answer:37 J

Explanation:

Given

Step :1

Heat added Q=44 J

Work done=-20 J

\Delta E_1=Q+W=44-20=24 J

Step :2

Heat added Q=-61 J

work done W_2

\Delta E_2=Q+W_2

\Delta E_2=61+W_2

\Delta E_1+\Delta E_2=0

as the process is cyclic

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