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11111nata11111 [884]
3 years ago
7

HELP PLEASE!!!! What is the net force on this object?

Physics
2 answers:
Ede4ka [16]3 years ago
4 0

The 20N straight up exactly cancels the 20N straight down.  So we can see that there's no net <em><u>vertical</u></em> force on the object, and if there's ANY net force on it at all, it's going to be horizontal.

The 14N force toward the left can't cancel the whole 22N toward the right.  It can only cancel 14N of it, and then there's still another 8N more toward the right.

So the net force on the object is <em>8N toward the right</em>.

rusak2 [61]3 years ago
3 0

the answer to this question is 8 newtons

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Answer:

a). Maximum Length L=0.929m

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the step that give the person forms a triangle whose two sides are known and the angle that forms between them, then using trigonometry as the image

Divide the original triangle in two and form a right triangle so the angle is 25 and the L is hypotenuse and the opposite is the step length

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sin(\alpha) =\frac{op}{h}

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T1=2\pi *\sqrt{\frac{L}{g}} \\T1=2\pi *\sqrt{\frac{1.1m}{9.8\frac{m}{s^{2}}}}\\ T1=2.1 Hz

The period is the inverse of the time of the motion so, the T1 is faster that the T because

t=\frac{1}{T1}=t= \frac{1}{2.1}=0.47s

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The speed is the relation between the distance with time so:

Vt=\frac{0.928m}{1.2s} \\Vt=0.773 \frac{m}{s} \\Vt=\frac{0.928m}{0.475s} \\Vt=1.953 \frac{m}{s}

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