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3 years ago

HELP PLEASE!!!! What is the net force on this object?

Physics

2 answers:

Ede4ka [16]3 years ago

4 0

The 20N straight up exactly cancels the 20N straight down. So we can see that there's no net vertical force on the object, and if there's ANY net force on it at all, it's going to be horizontal.

The 14N force toward the left can't cancel the whole 22N toward the right. It can only cancel 14N of it, and then there's still another 8N more toward the right.

So the net force on the object is 8N toward the right.

rusak2 [61]3 years ago

3 0

the answer to this question is 8 newtons

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A slingshot can project a pebble at a speed as high as 38.0 m/s. (a) If air resistance can be ignored, how high (in m) would a p

kipiarov [429]

Answer:

73.67 m

Explanation:

If projected straight up, we can work in 1 dimension, and we can use the following kinematic equations:

$y(t) = y_0 + V_0 * t + \frac{1}{2} a t^2$

$V(t) = V_0 + a * t$ ,

Where $y_0$ its our initial height, $V_0$ our initial speed, a the acceleration and t the time that has passed.

For our problem, the initial height its 0 meters, our initial speed its 38.0 m/s, the acceleration its the gravitational one ( g = 9.8 m/s^2), and the time its uknown.

We can plug this values in our equations, to obtain:

$y(t) = 38 \frac{m}{s} * t - \frac{1}{2} g t^2$

$V(t) = 38 \frac{m}{s} - g * t$

note that the acceleration point downwards, hence the minus sign.

Now, in the highest point, velocity must be zero, so, we can grab our second equation, and write:

$0 m = 38 \frac{m}{s} - g * t$

and obtain:

$t = 38 \frac{m}{s} / g$

$t = 38 \frac{m}{s} / 9.8 \frac{m}{s^2}$

$t = 3.9 s$

Plugin this time on our first equation we find:

$y = 38 \frac{m}{s} * 3.9 s - \frac{1}{2} 9.8 \frac{m}{s^2} (3.9 s)^2$

$y=73.67 m$

6 0

3 years ago

I only need help with the two bottom questions! Please help though!!!

kompoz [17]

If the rabbits died out, the other organisms would be likely to die. (If that were their main source of food.)

producer- something that produces food for other organisms (and is consumed). ex.grass

primary consumers- eat the producers and like first. ex. rabbit
secondary consumer- eats the primary consumers

Scavenger - is basically an organism that scavenges for food ex. vulture.

good luck!

3 0

3 years ago

1. A race car accelerates at a rate of 15.6 m/s. If it starts from rest, how much time till it

musickatia [10]

Answer: 5.79 s

Explanation:

Vs=0 m/s starting speed(from rest)

Vf=325 km/h= 325*1000/3600= 90.28 m/s

a=15.6m/s²

Using equation for acceleration we can find out time :

a=(Vf-Vs)/t

t=(Vf-Vs)/a

t=(90.28 m/s-0m/s)/15.6 m/s²

t=5.79 s

4 0

3 years ago

What is the speed of light with N=1.33

alexgriva [62]

If the refractive index of some substance is 1.33, then
the speed of light in that substance is

 (speed of light in vacuum) / (1.33) =

 (299,792,458 m/s) / (1.33) = 225,407,863 m/s

3 0

3 years ago

Read 2 more answers

What is meant by infinite slew rate

Dennis_Churaev [7]

Am infinite slew rate means that the changes in the output voltage occur immensely when the input voltage changes.
Slew rate is measurement of the response of an operational amplifier. For an ideal operational amplifier, time delay is negligible. Hence it has an infinite slew rate.
In simpler terms it means that it can provide output voltage simultaneously with the input voltage changes.

Hope this helps :)

3 0

2 years ago