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andrew11 [14]
3 years ago
7

Why would a ball-and-socket joint at the knees create problems for walking?

Biology
1 answer:
Morgarella [4.7K]3 years ago
5 0
There is not a ball<span> and </span>socket joint at the knee<span>. It is a complex hinge </span>joint<span>. The </span>knee joint<span> begins to wear out from </span>walking<span> and carrying most of our weight. Hope this answers the question. Have a nice day. Feel free to ask more questions.</span>
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How does the Foucault Pendulum show that the Earth rotates?
egoroff_w [7]

The Foucault Pendulum show that the Earth rotates because the pendulum would swing so slowly that it would appear to change direction as the Earth moved away.

<h3>How does the Foucault pendulum work?</h3>

The Foucault pendulum was able to demonstrate experimentally that the Earth revolves around itself with an angular velocity Ω, in a period of 23 hours, 56 minutes and 4 seconds.

Thus, Foucault knew that the longer the string attached to the weight, the slower the swing of his pendulum. He could attach the string above to an almost frictionless pin, and if he used a very large weight, the pendulum would swing so slowly that it would appear to change direction as the Earth moved away.

See more about pendulum at brainly.com/question/14759840

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7 0
2 years ago
Igneouse instructions injected bettwen horizon layers are what
Nutka1998 [239]

your answer is sills

5 0
2 years ago
Considering the same population of cats as in Part A, what is the expected frequency of each genotype (TLTL, TLTS, TSTS ) based
zaharov [31]

Answer:

P = f(TLTL) = 0,16

H = f(TLTS) = 0,48

Q = f(TSTS) = 0,36

Explanation:

Hello!

The allele proportion of any locus defines the genetic constitution of a population. Its sum is 1 and its values ​​can vary between 0 (absent allele) and 1 (fixed allele).

The calculation of allelic frequencies of a population is made taking into account that homozygotes have two identical alleles and heterozygotes have two different alleles.

In this case, let's say:

f(TL) = p

f(TS) = q

p + q = 1

Considering the genotypes TLTL, TLTS, TSTS, and the allele frequencies:

TL= 0,4

TS= 0,6

Genotypic frequency is the relative proportion of genotypes in a population for the locus in question, that is, the number of times the genotype appears in a population.

P = f(TLTL)

H = f(TLTS)

Q = f(TSTS)

Also P + H + Q = 1

And using the equation for Hardy-Weinberg equilibrium, the genotypic frequencies of equilibrium are given by the development of the binomial:

p^{2} = f(TLTL)

2pq = f(TSTL)

q^{2} = f(TSTS)

So, if the population is in balance:

P = p^{2}

H = 2pq

Q = q^{2}

Replacing the given values of allele frecuencies in each equiation you can calculate the expected frequency of each genotype for the next generation as:

f(TLTL) = P = p^{2} = 0,4^{2} = 0,16

f(TLTS) = H = 2pq = 2*0,4*0,6 = 0,48

f(TSTS) = Q = q^{2} = 0,6^{2} = 0,36

I hope you have a SUPER day!

6 0
3 years ago
Who an help me science
aleksandr82 [10.1K]

It would be A; Or 0 because since the dominate trait is being able to roll the tongue, it over rules the recessive.

3 0
3 years ago
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Which event would be the result if populations of producers in an ecosystem became unstable?
pychu [463]

Answer:

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Explanation:

5 0
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