There are 9 choices for the first digit: {0, 1, 2, 3, 4, 5, 7, 8, 9}
There are 10 choices for the second digit: {0, 1, 2, 3, 4, 5, 6, 7, 8, 9}
There are 10 choices for the third digit: {0, 1, 2, 3, 4, 5, 6, 7, 8, 9}
There are 5 choices for the fourth digit: {0, 2, 4, 6, 8}
Multiply the number of choices per digit to get: 9*10*10*5 = 90*50 = 4500
Answer: 4500
Answer:
z = 2.1
Step-by-step explanation:

This tells us that the person's score of 121 places them 2.1 standard deviations above the mean score of 79.
I’m not smart and I’m not saying its right but 50,000