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adell [148]
3 years ago
7

Which of the following best describes the safety of blogging

Computers and Technology
1 answer:
Pavlova-9 [17]3 years ago
3 0
We need the options
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A technician installs a new WAP and users in the area begin to report poor performance. The technician uses a ping and only 3 of
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Your company's IT management team is looking for an online tool to provide recommendations to save money, improve system availab
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6 0
3 years ago
Create a function void process(char ch, int x, int y)- to accept an arithmetic operator (+,-./, in argum
saul85 [17]

Answer:

The program is as follows:

import java.util.*;

public class Main{

   public static void process(char ch, int x, int y){

if(ch == '+'){

    System.out.print(x+y);  }

else if(ch == '-'){

    System.out.print(x-y);  }

else if(ch == '*'){

    System.out.print(x*y);  }

else if(ch == '/'){

    if(y!=0){

        double num = x;

        System.out.print(num/y);      }

    else{

        System.out.print("Cannot divide by 0");     } }

else{

    System.out.print("Invalid operator"); }

 }

public static void main(String[] args) {

 Scanner input = new Scanner(System.in);

 int x, y;

 char ch;

 System.out.print("Enter two integers: ");

 x = input.nextInt(); y = input.nextInt();

 System.out.print("Enter operator: ");

 ch = input.next().charAt(0);  

 process(ch,x, y);

}

}

Explanation:

The function begins here

   public static void process(char ch, int x, int y){

If the character is +, this prints the sum of both integers

<em> if(ch == '+'){</em>

<em>     System.out.print(x+y);  }</em>

If the character is -, this prints the difference of both integers

<em> else if(ch == '-'){</em>

<em>     System.out.print(x-y);  }</em>

If the character is *, this prints the product of both integers

<em> else if(ch == '*'){</em>

<em>     System.out.print(x*y);  }</em>

If the character is /, this prints the division of both integers.

<em> else if(ch == '/'){</em>

<em>     if(y!=0){</em>

<em>         double num = x;</em>

<em>         System.out.print(num/y);      }</em>

<em>     else{</em>

<em>This is executed if the denominator is 0</em>

<em>         System.out.print("Cannot divide by 0");     } }</em>

Invalid operator is printed for every other character

<em>else{</em>

<em>     System.out.print("Invalid operator"); }</em>

<em> </em> }

The main begins here

public static void main(String[] args) {

 Scanner input = new Scanner(System.in);

This declares both integers

 int x, y;

This declares the operator

 char ch;

Get input for both integers

<em>  System.out.print("Enter two integers: ");</em>

<em>  x = input.nextInt(); y = input.nextInt();</em>

Get input for the operator

<em>  System.out.print("Enter operator: ");</em>

<em>  ch = input.next().charAt(0);   </em>

Call the function

 process(ch,x, y);

}

}

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3 years ago
After setting up an Internet connection, you cannot connect to Internet websites, just company intranet sites. What is MOST like
Masteriza [31]

Answer:Proxy setting

Explanation:

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