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2 years ago

Heather levantó un juguete con una masa de 7/12 de kilogramo. Luego otro juguete con una masa de 1/12 de kilogramo.

Mathematics

2 answers:

Alex2 years ago

8 0

Yo tenia esa pregumt

rusak2 [61]2 years ago

7 0

responder: 8/12

explicación: Si suma los dos numeradores, obtiene 8/12

evidencia: 7/12 + 1/12

7+1= 8/12

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Hello pls help meeee )

In-s [12.5K]

Answer:

(4, 1)

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

Multiplication Property of Equality
Division Property of Equality
Addition Property of Equality
Subtraction Property of Equality

Algebra I

Terms/Coefficients
Coordinates (x, y)
Solving systems of equations using substitution/elimination

Step-by-step explanation:

Step 1: Define Systems

y = 2x - 7

y = -x + 5

Step 2: Solve for x

Substitution

Substitute in y: 2x - 7 = -x + 5
[Addition Property of Equality] Isolate x terms: 3x - 7 = 5
[Addition Property of Equality] Isolate x term: 3x = 12
[Division Property of Equality] Isolate x: x = 4

Step 3: Solve for y

Define original equation: y = -x + 5
Substitute in x: y = -4 + 5
Add: y = 1

7 0

3 years ago

Which equation is not equvilant to A=1/2 bh,

ollegr [7]

Which equation is not equvilant It is c

3 0

3 years ago

You have a bag of chocolate candy. Ten of them are red, 7 are brown, 12 are green, and 9 are blue. What is the probability that

Brrunno [24]

It would be $\frac{10}{38}$ , or, in simplest form, $\frac{5}{19}$ .

You get this by adding all the marbles to find the total number of marbles. 10+7+12+9, which equals 38.

You have 10 red marbles out of 38 total, so that is represented by $\frac{10}{38}$ !

5 0

3 years ago

Read 2 more answers

Suppose a consumer group suspects that the proportion of households that have three cell phones NOT known to be 30%. A cell phon

leva [86]

Answer:

We conclude that the actual percentage of households is equal to 30%.

Step-by-step explanation:

We are given that a consumer group suspects that the proportion of households that have three cell phones NOT known to be 30%.

Their marketing people survey 150 households with the result that 43 of the households have three cell phones.

Let p = proportion of households that have three cell phones NOT known.

So, Null Hypothesis, $H_0$ : p = 30% {means that the actual percentage of households is equal to 30%}

Alternate Hypothesis, $H_A$ : p $\neq$ 30% {means that the actual percentage of households different from 30%}

The test statistics that would be used here One-sample z-test for proportions;

T.S. = $\frac{\hat p-p}{\sqrt{\frac{p(1-p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of households having three cell phones = $\frac{43}{150}$ = 0.29

n = sample of households = 150

So, the test statistics = $\frac{0.29-0.30}{\sqrt{\frac{0.30(1-0.30)}{150} } }$

= -0.27

The value of z test statistic is -0.27.

Also, P-value of the test statistics is given by;

P-value = P(Z < -0.27) = 1 - P(Z $\leq$ 0.27)

= 1 - 0.6064 = 0.3936

Now, at 1% significance level the z table gives critical value of -2.58 and 2.58 for two-tailed test.

Since our test statistic lies within the range of critical values of z, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which we fail to reject our null hypothesis.

Therefore, we conclude that the actual percentage of households is equal to 30%.

4 0

3 years ago

Write the expression a2b3c2d in expanded form.

Zanzabum

Answer:

a*2+b*2+c*2+d

Step-by-step explanation:

If i's meant to be Pythagorean theorem, a*a+b*b=c*c

8 0

3 years ago