Answer:
(1,6) , (2,7) , (3,8) , (4,9) , (5,10)
Step-by-step explanation:
Given equation: y = x + 5
when x = 1, y = 1 + 5 = 6
(1,6)
when x = 2, y = 7
(2,7)
when x = 3 , y = 8
(3,8)
when x = 4 , y = 9
(4,9)
when x = 5 , y = 10
(5,10)
Answer:
2√6
Step-by-step explanation:
I will be honest with you and say that I'm not sure if it is right or not.
Answer:
![\dfrac{\sqrt[12]{55296}}{2}](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Csqrt%5B12%5D%7B55296%7D%7D%7B2%7D)
Step-by-step explanation:
Rationalize the denominator, then use a common root for the numerator.
![\dfrac{\sqrt[4]{6}}{\sqrt[3]{2}}=\dfrac{(2\cdot 3)^{\frac{1}{4}}}{2^{\frac{1}{3}}}\\\\=\dfrac{(2\cdot 3)^{\frac{1}{4}}}{2^{\frac{1}{3}}}\cdot\dfrac{2^{\frac{2}{3}}}{2^{\frac{2}{3}}}=\dfrac{2^{\frac{1}{4}+\frac{2}{3}}3^{\frac{1}{4}}}{2}\\\\=\dfrac{2^{\frac{11}{12}}3^{\frac{3}{12}}}{2}=\dfrac{\sqrt[12]{2^{11}3^{3}}}{2}\\\\=\dfrac{\sqrt[12]{55296}}{2}](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Csqrt%5B4%5D%7B6%7D%7D%7B%5Csqrt%5B3%5D%7B2%7D%7D%3D%5Cdfrac%7B%282%5Ccdot%203%29%5E%7B%5Cfrac%7B1%7D%7B4%7D%7D%7D%7B2%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D%7D%5C%5C%5C%5C%3D%5Cdfrac%7B%282%5Ccdot%203%29%5E%7B%5Cfrac%7B1%7D%7B4%7D%7D%7D%7B2%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D%7D%5Ccdot%5Cdfrac%7B2%5E%7B%5Cfrac%7B2%7D%7B3%7D%7D%7D%7B2%5E%7B%5Cfrac%7B2%7D%7B3%7D%7D%7D%3D%5Cdfrac%7B2%5E%7B%5Cfrac%7B1%7D%7B4%7D%2B%5Cfrac%7B2%7D%7B3%7D%7D3%5E%7B%5Cfrac%7B1%7D%7B4%7D%7D%7D%7B2%7D%5C%5C%5C%5C%3D%5Cdfrac%7B2%5E%7B%5Cfrac%7B11%7D%7B12%7D%7D3%5E%7B%5Cfrac%7B3%7D%7B12%7D%7D%7D%7B2%7D%3D%5Cdfrac%7B%5Csqrt%5B12%5D%7B2%5E%7B11%7D3%5E%7B3%7D%7D%7D%7B2%7D%5C%5C%5C%5C%3D%5Cdfrac%7B%5Csqrt%5B12%5D%7B55296%7D%7D%7B2%7D)
The sum of all the measurements is just the average times the number.


So if the average of all 92 is 7 the sum of those is

The average of the last two is 7.2 so their sum is

That means the sum of the first 90 is

so the average of the first 90 is

cm