Answer:
a) shown
b) h = [sqrt(17) - (5/2)t]²
c) t = 2sqrt(17)/5 seconds
Step-by-step explanation:
V = pi × r² × h
V = pi × 5² × h
V = 25pi × h
a) dV/dt = dV/dh × dh/dt
-5pi × sqrt(h) = 25pi × dh/dt
dh/dt = -sqrt(h)/5
b) 1/sqrt(h) .dh = -5. dt
2sqrt(h) = -5t + c
t = 0, h = 17
2sqrt(17) = 0 + c
c = 2sqrt(17)
2sqrt(h) = -5t + 2sqrt(17)
sqrt(h) = [2sqrt(17) - 5t] ÷ 2
sqrt(h) = sqrt(17) - (5/2)t
Square both sides
h = [sqrt(17) - (5/2)t]²
c) empty: h = 0
0 = [sqrt(17) - (5/2)t]²
sqrt(17) - (5/2)t = 0
(5/2)t = sqrt(17)
t = 2sqrt(17)/5
t = 1.64924225 seconds
sqrt: square root
Answer: the average speed is 7.5 mph or at least im pretty sure
Step-by-step explanation:
This is because if you make the 2 miles at 6 mph to 1 mile at 3 mph then you get 1 mile at 3mph and 1 mile at 12 mph. now that you have the unit rates of these you can add them. 1 + 1 = 2 miles and 3 + 12 = 15 mph now divide this by two and you get 7.5 mph per mile.
I hope this helped, if it did could you give me a good rating? lol
The answer is 24 now goodluck with your homework
Answer: 50 ft
Step-by-step explanation:
The correct function is h(t)=-16t^2+200t+50.
Hi, to answer this question we simply have to replace t =0 in the function given:
h(t)=-16t^2+200t+50.
h (0) = -16t^2+200t+50.
h(0) = 50
When the time is 0, the rocket is at the top of the building.
The rocket was launched from a 50 ft height.
Feel free to ask for more if needed or if you did not understand something.
Answer:
53.04
Step-by-step explanation:
