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2 years ago

What is the distance across the lake?

Mathematics

2 answers:

fredd [130]2 years ago

7 0

Answer:

x = 15.008

Step-by-step explanation:

9^2 + x^2 = 17.5^2

x^2=225.25

x = 15.008

Advocard [28]2 years ago

6 0

Answer:

you have to use the formula

Step-by-step explanation:

length times with time height

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MATH HELP!!!!!!!!! PLS PLS I need help

Ahat [919]

Answer:

2 7/13

Step-by-step explanation:

6 0

2 years ago

2,000.h for h = 0.004<br> 2,000 h =

Gekata [30.6K]

Answer:

$h=2\times 10^6$

Step-by-step explanation:

We need to find h for the following condition.

2,000×h = 0.004

Dividing both sides by 2000

$\dfrac{2000h}{2000}=\dfrac{0.004}{2000}\\\\h=0.000002\\\\h=2\times 10^6$

So, the value of h is equal to $2\times 10^6$ .

8 0

2 years ago

Cathy made chocolate peanut butter fudge. She made enough chocolate fudge to fill 5 boxes. If she made 2/3 as much peanut butter

lisov135 [29]

Answer: 3¹/₃ boxes

Step-by-step explanation:

She made enough fudge to fill up 5 boxes then made 2/3 as much peanut butter.

To find out the number of boxes the peanut butter would fill, simply find out what is 2/3 of 5 boxes:

= 2/3 * 5

= 3.33 boxes

= 3¹/₃ boxes

6 0

3 years ago

The label on the cars antifreeze container claims to protect the car between -30C and 130C. To convert Celsius temperature to Fa

RideAnS [48]

C = 5/9(F - 32)

C = -30
-30 = 5/9(F - 32)
-30 = 5/9F - 160/9
-30 + 160/9 = 5/9F
-270/9 + 160/9 = 5/9F
-110/9 = 5/9F
-110/9 * 9/5 = F
- 990/45 = F
- 22 = F

C = 5/9(F - 32)
C = 130

130 = 5/9F - 160/9
130 + 160/9 = 5/9F
1170/9 + 160/9 = 5/9F
1330/9 = 5/9F
1330/9 * 9/5 = F
11970/45 = F
266 = F

So in Fahrenheit temp, the the car is protected between -22 F and 266 F

4 0

3 years ago

Read 2 more answers

Given that (ax^2 + bx + 3) (x + d) = x^3 + 6x^2 + 11x + 12<br> a + 2b - d = ?

Mariulka [41]

Answer:

Let's solve for a.

(ax2+bx+3)(x+d)=x3+6x2+11x+12a+2b−d

Step 1: Add -12a to both sides.

adx2+ax3+bdx+bx2+3d+3x+−12a=x3+6x2+12a+2b−d+11x+−12a

adx2+ax3+bdx+bx2−12a+3d+3x=x3+6x2+2b−d+11x

Step 2: Add -bdx to both sides.

adx2+ax3+bdx+bx2−12a+3d+3x+−bdx=x3+6x2+2b−d+11x+−bdx

adx2+ax3+bx2−12a+3d+3x=−bdx+x3+6x2+2b−d+11x

Step 3: Add -bx^2 to both sides.

adx2+ax3+bx2−12a+3d+3x+−bx2=−bdx+x3+6x2+2b−d+11x+−bx2

adx2+ax3−12a+3d+3x=−bdx−bx2+x3+6x2+2b−d+11x

Step 4: Add -3d to both sides.

adx2+ax3−12a+3d+3x+−3d=−bdx−bx2+x3+6x2+2b−d+11x+−3d

adx2+ax3−12a+3x=−bdx−bx2+x3+6x2+2b−4d+11x

Step 5: Add -3x to both sides.

adx2+ax3−12a+3x+−3x=−bdx−bx2+x3+6x2+2b−4d+11x+−3x

adx2+ax3−12a=−bdx−bx2+x3+6x2+2b−4d+8x

Step 6: Factor out variable a.

a(dx2+x3−12)=−bdx−bx2+x3+6x2+2b−4d+8x

Step 7: Divide both sides by dx^2+x^3-12.

a(dx2+x3−12)

dx2+x3−12

−bdx−bx2+x3+6x2+2b−4d+8x

dx2+x3−12

−bdx−bx2+x3+6x2+2b−4d+8x

dx2+x3−12

Answer:

−bdx−bx2+x3+6x2+2b−4d+8x/

dx2+x3−12

Step-by-step explanation:

8 0

2 years ago

What is the distance across the lake?​

What is the distance across the lake?