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QveST [7]
3 years ago
7

What is the value of "x" if 25^2 = x

Mathematics
1 answer:
olga55 [171]3 years ago
5 0
The value of x would be the answer of 25^2 which means it is squared and squaring means a number times itself, so, therefore you have 25x25 which would give you the answer of 625 meaning x=625
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One number is six less than a second number. Six times the first is 8 more than 4 times the second. Find the numbers.
irinina [24]

Answer:

x-6=y

6x= 8+4y

Step-by-step explanation:

3 0
4 years ago
HELP someone please!!!! i dont understand
ad-work [718]

Answer:

x = 65.03°

Step-by-step explanation:

To solve for x, we have to apply trigonometric ratio.

Recall: SOH CAH TOA

From the diagram, we know the following:

Reference angle = x

Hypotenuse = 45

Adjacent = 19

Since we know the Hyp and Adj, we would apply CAH, which is:

Cos x = Adj/Hyp

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3 years ago
Solve 75=125 (0.8)t^
valentinak56 [21]
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7 0
3 years ago
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Solve the following 3 × 3 system. Enter the coordinates of the solution below.
love history [14]
The system is:

i)    <span>2x – 3y – 2z = 4
ii)    </span><span>x + 3y + 2z = –7
</span>iii)   <span>–4x – 4y – 2z = 10 

the last equation can be simplified, by dividing by -2, 

thus we have:

</span>i)    2x – 3y – 2z = 4
ii)    x + 3y + 2z = –7
iii)   2x +2y +z = -5 


The procedure to solve the system is as follows:

first use any pairs of 2 equations (for example i and ii, i and iii) and equalize them by using one of the variables:

i)    2x – 3y – 2z = 4   
iii)   2x +2y +z = -5 

2x can be written as 3y+2z+4 from the first equation, and -2y-z-5 from the third equation.

Equalize:  

3y+2z+4=-2y-z-5, group common terms:
5y+3z=-9   

similarly, using i and ii, eliminate x:

i)    2x – 3y – 2z = 4
ii)    x + 3y + 2z = –7

multiply the second equation by 2:


i)    2x – 3y – 2z = 4
ii)    2x + 6y + 4z = –14

thus 2x=3y+2z+4 from i and 2x=-6y-4z-14 from ii:

3y+2z+4=-6y-4z-14
9y+6z=-18

So we get 2 equations with variables y and z:

a)   5y+3z=-9 
b)   9y+6z=-18

now the aim of the method is clear: We eliminate one of the variables, creating a system of 2 linear equations with 2 variables, which we can solve by any of the standard methods.

Let's use elimination method, multiply the equation a by -2:

a)   -10y-6z=18 
b)   9y+6z=-18
------------------------    add the equations:

-10y+9y-6z+6z=18-18
-y=0
y=0,

thus :
9y+6z=-18 
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z=-3

Finally to find x, use any of the equations i, ii or iii:

<span>2x – 3y – 2z = 4 
</span>
<span>2x – 3*0 – 2(-3) = 4

2x+6=4

2x=-2

x=-1

Solution: (x, y, z) = (-1, 0, -3 ) 


Remark: it is always a good attitude to check the answer, because often calculations mistakes can be made:

check by substituting x=-1, y=0, z=-3 in each of the 3 equations and see that for these numbers the equalities hold.</span>
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The factors are 3 6 and 9
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3 years ago
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