What is the mean absolute deviation for 545 620 775 775 810 905 950 and 1120
1 answer:
To solve this question, we know we have to find the Mean Absolute Deviation. That means that we have to add all the numbers that we were given, find the mean of them, find how much all of the numbers stray away from the mean, and then find the average of how far these numbers stray away from the mean.
The first step is to find the mean.
=
=
=
=812.5 That means the mean is 812.5. Now we need to find how much each of the values deviates from the mean (for simplicity's sake, I will use 813 as the mean).
545 deviates 268, 620 deviates 193, 775 deviates 38, 775 deviates 38, 810 deviates 3, 905 deviates 92, 950 deviates 137, and 1120 deviates 307. Now we need to find the average of these quantities. After doing all the math, one can figure out that the average for these numbers is 134.5, meaning that the Mean Absolute Deviation for these numbers is 134.5.
The first step is to find the mean.
=
=812.5 That means the mean is 812.5. Now we need to find how much each of the values deviates from the mean (for simplicity's sake, I will use 813 as the mean).
545 deviates 268, 620 deviates 193, 775 deviates 38, 775 deviates 38, 810 deviates 3, 905 deviates 92, 950 deviates 137, and 1120 deviates 307. Now we need to find the average of these quantities. After doing all the math, one can figure out that the average for these numbers is 134.5, meaning that the Mean Absolute Deviation for these numbers is 134.5.
You might be interested in
Answer: QS and QR are the shortest segment of the triangle ΔPQS, and ΔSQR respectively.
Step-by-step explanation:
Since we have given that
ΔPQS, and ΔSQR,
Consider, ΔPQS,
As we know that " the length opposite to the largest angle is the shortest segment."
So, According to the above statement.
Similarly,
Consider, ΔSQR,
Again applying the above statement, we get that,
Hence, QS and QR are the shortest segment of the triangle ΔPQS, and ΔSQR respectively.