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lozanna [386]
2 years ago
13

What is the mean absolute deviation for 545 620 775 775 810 905 950 and 1120

Mathematics
1 answer:
zavuch27 [327]2 years ago
7 0
To solve this question, we know we have to find the Mean Absolute Deviation. That means that we have to add all the numbers that we were given, find the mean of them, find how much all of the numbers stray away from the mean, and then find the average of how far these numbers stray away from the mean. 

The first step is to find the mean. 
\frac{545 + 620 + 775 + 775 + 810  + 905 + 950 + 1120}{8}=
=\frac{6500}{8}=
=812.5      That means the mean is 812.5. Now we need to find how much each of the values deviates from the mean (for simplicity's sake, I will use 813 as the mean). 

545 deviates 268, 620 deviates 193, 775 deviates 38, 775 deviates 38, 810 deviates 3, 905 deviates 92, 950 deviates 137, and 1120 deviates 307. Now we need to find the average of these quantities. After doing all the math, one can figure out that the average for these numbers is 134.5, meaning that the Mean Absolute Deviation for these numbers is 134.5.

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<span>D. The Baum family pays $78.25 more than the Freeman family.</span> 
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3 years ago
A freight trains departs from one train station to its destination at a constant speed. Suppose the distance the train is from t
marysya [2.9K]

Answer:

Distance = 54 miles (Approx)

Step-by-step explanation:

Given:

Co-ordinate of two point = (0.5,135) and (2,81)

Find:

Distance

Computation:

Distance = √(x1-x2)²+(y1-y2)²

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6 0
3 years ago
184 is what percent more than 148
Alika [10]
It is 36 percent more
7 0
2 years ago
Which expression is equivalent to the one below?
FromTheMoon [43]
9 divided by 13 = 9/13

None of the answer above
Should be: 9 • 1/13
7 0
3 years ago
The table below shows all outcomes for rolling 2 dice. The bold numbers 1 through 6 show the possible results for each die. All
Leokris [45]

Part I:

1. If you have to circle each outcome in the table that at least 1 die is a 4, then you have to circle row corresponding to the number 4 and column corresponding to the number 4.

2. If you have to cross out each outcome where the sum of the dice is greater than 5, then you have to cross out all not bold numbers 6, 7, 8, 9, 10, 11 and 12 in the table.

Part II:

Here you can see 36 possible outcomes.

1. The probability that at least 1 die is a 4 is:

Pr(A)=\dfrac{11}{36} - (favorable outcomes are 4+1=5, 4+2=6, 4+3=7, 4+4=8, 4+5=9, 4+6=10, 1+4=5, 2+4=6, 3+4=7, 5+4=9, 6+4=10).

2. The probability that the sum of the dice is greater than 5 is:

Pr(B)=\dfrac{26}{36}=\dfrac{13}{18}.

3. The probability that at least 1 die is a 4 and that the sum of the dice is greater than 5 is

Pr(A\cap B)=\dfrac{9}{36}=\dfrac{1}{4}.

4. The probability that at least 1 die is a 4 or that the sum of the dice is greater than 5 is:

Pr(A\cup B)=\dfrac{28}{36}=\dfrac{7}{9}.

4 0
3 years ago
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