More then 2 thats the only answer I can give
(24xy^3-16x^2y^2+32x^2y)/8xy
<span><span>(<span><span><span><span><span><span><span>24x</span><span>y^3</span></span>−<span><span>16<span>x^2</span></span><span>y^2</span></span></span>+<span><span>32<span>x^2</span></span>y</span></span>8</span></span>x</span>)</span><span>(y)</span></span><span> =<span><span><span>−<span><span>2<span>x^3</span></span><span>y^3</span></span></span>+<span><span>3<span>x^2</span></span><span>y^4</span></span></span>+<span><span>4<span>x^3</span></span><span>y^<span>2</span></span></span></span></span>
5.70c + 9.80a = 1526.60
a = 4c
5.70c + 9.80(4c) = 1526.60
5.70c + 39.20c = 1526.60
44.90c = 1526.60
c = 1526.60/44.90
c = 34 <=== child tickets sold
a = 4c
a = 4(34)
a = 136 ...adult tickets sold
5 squared is 5x5. And 2 cubed is 2x2x2. So, the answer would be 200.
