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andrey2020 [161]
2 years ago
12

Determine the shortest segment in △ PQS and △ QRS. Remember that a segment is named by its endpoints (two letters).

Mathematics
1 answer:
irinina [24]2 years ago
8 0

Answer: QS and QR are the shortest segment of the triangle ΔPQS, and ΔSQR respectively.

Step-by-step explanation:

Since we have given that

ΔPQS, and ΔSQR,

Consider, ΔPQS,

As we know that " the length opposite to the largest angle is the shortest segment."

So, According to the above statement.

\angle QPS=63\textdegree\\\\\text{So, QS is the shortest segment of this triangle}

Similarly,

Consider, ΔSQR,

Again applying the above statement, we get that,

\angle QSR=75\textdegree\\\\\text{ So, QR is the shortest segment of this triangle}

Hence, QS and QR are the shortest segment of the triangle ΔPQS, and ΔSQR respectively.



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For what value of c will this function have one zero?<br> f(x) = X^2 +c
Phoenix [80]
X² + c is actually a quadratic function.

And x² + c = 0,  it usually has two zeros which are solutions.

But for when c = 0,

x² + c = 0

x² + 0 = 0

x² = 0

Taking the square root of both sides.

x = 0.  Here it only has one zero.

So the function x² + c,  only has one root for  c = 0.
6 0
2 years ago
if the diameter of a cone is 16cm and the height is 15cm what is the volume? I've tried the formula v=1/3*3.14*r^2*h but the ans
Alisiya [41]

Answer:

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A= area of base 3

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3

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3

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5 0
2 years ago
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Rom4ik [11]
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Thunderclan89
7 0
3 years ago
What are the values of the coefficients and constant term of 0 = 4 – 7x2 + x in standard form?
katen-ka-za [31]

ANSWER

a =  - 7

b = 1

c = 4

EXPLANATION

The given quadratic equation is:

0 = 4 - 7 {x}^{2}  + x

We rewrite in the standard quadratic equation form to obtain,

- 7 {x}^{2}  + x + 4 = 0

Comparing this to the general standard quadratic equation.

a {x}^{2}  + bx + c = 0

We have my

a =  - 7

b = 1

c = 4

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3 years ago
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