decreased primary consumer
Answer:
5.) The possible genotypes should be: RR RB BB ( if the could for the same proteins)
6.) Frequency of R: 0.5
7.)Frequency of R: 0.5
8.)Frequency of R: 0.375
Explanation:
5.) If R and B code for the different forms of the same protein then they are only a few possible out comes
6.) First calculate the total alleles in population
allele R= 40
Allele B=40
total allele = R+B= 40+40
=80
Now to find allele R frequency is:
(Total R alleles) / (Total allele in pop)
40/80=
0.5
7.)Calculate the total alleles
Alleles from for R
RR= 10
R=10x 2= 20
Multiply the value by 2 because there are 2 R alleles present in
RB=20
R=20
Number doesn't change there is only 1 R allele
Total R=20+20
=40
Alleles For B
BB=10
B=10×2
=20
Same thing here, two B alleles together so multiple by 2
RB=20
B=20
Total B= 20+20
=40
Total alleles in pop add
40+40
=80
Frequency of R
Total of R/Total Alleles
=40/80
=0.5
8.)Repeat the same thing in 7 but use different numbers
RR=10
R=10x2
=20
RB=10
R=10
Total R= 20+10
=30
We use Chargaff's rule to get the answer.
[A] + [G] = [C]+ [T].
[A] + [G] + [C] + [T] = 100%
Where is A is Adenine, G is Gaunine, T is Thymine and C is Cytosine.
In DNA, Adenine always pairs with Thymine, and Guanine always pairs with Cytosine.
Therefore if Thymine is 35%, then Adenine will also be 35% to make 70% in total.
The remaining percentage will be 100% - 70% = 30%.
The 30% will be shared equally among Cytosine and Guanine, at 15% each. Therefore Cytosine will be 15%
prokaryotic cells do not have a nucleus.
The answer is it's combination of alleles for a specific one.
