Answer:
24
Step-by-step explanation:
Varies directly means that something constant times l equals V or V=kl where k is that constant.
Plug in point given 288=k(12) and solve the constant of proportionality by dividing both sides by 12.
k=288/12=24
Answer:
5
Step-by-step explanation:
95+8=103
95+3=98
103-98=5
Answer:
557.89
Step-by-step explanation:
Download photomath on Appstore it'll help you explain. but basically you multiply each digit at the bottom to the whole number on the top
23.50
<u>x </u><u>23.74</u>
940 ====== 23.50 multiply to 4
16450 ====== 23.50 multiply to 7
70500 ====== 23.50 multiply to 3
<u>+ 470000 </u> ====== 23.50 multiply to 2
557.890 ====== Add all the numbers together, move the decimal sign down to align with the result
<u />
To do this we need to move 10 to other side. To accomplish this you just need to add 10 to both side since (-10)
so
A+ 10 = c -10 + 10
we get
A+ 10 = c
lets say it wasn't -10 but positive 10.
A = c + 10 then we would subtract 10 from both sides
A -10 = c + 10 - 10
we get
A - 10 = C
Answer:
The chances of Yvonne to get a blue berry candy in the two cases are 1 and 1/2 in case 1 and 2/3 in the case 2.
Step-by-step explanation:
Maurice has a paper bag with three hard candies
2 blueberries and 1 green apple
Yvonne and Kate want 1 candy each
It is not mentioned that ether Kate has taken a candy already before Yvonne or not so we will consider both the cases
Case 1
If Kate has picked a candy before Yvonne
- If Kate gets an Apple green candy then the probability or Yvonne to get a Blueberry will be = 2/2 = 1 ( as there will 2 blueberry candy left in the bag)
- If Kate has taken a Blueberry candy then there will be 1 blueberry and 1 apple green candy in the bag so the probability of Yvonne to get a Blueberry candy will be = 1/2
Case 2
If Kate has not taken any candy from the bag before Yvonne
Probability that Yvonne will get a blueberry candy will be = 2/3
Therefore the chances of Yvonne to get a blue berry candy in the two cases are 1 and 1/2 in case 1 and 2/3 in the case 2.
