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3 years ago

Domain and Range for this equation? F(x)= 3x^7+0x^6-0x^5-2x^4-3x^3-2x^2-x^1+x^0

1 answer:

8 0

The domain is equal all real numbers
$D=\mathbb{R}$

The degrees of the polynomial is odd (3x^7, 7 is odd), therefore the range is equal all real numbers

$R=\mathbb{R}$

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A TV studio has brought in 8 boy kittens and 10 girl kittens for a cat food commercial.

kondor19780726 [428]

Answer:

0.323 = 32.3% probability that the director chooses 3 boy kittens and 5 girl kittens.

Step-by-step explanation:

The kittens are chosen without replacement, which means that the hypergeometric distribution is used to solve this question.

Hypergeometric distribution:

The probability of x sucesses is given by the following formula:

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

In which:

x is the number of sucesses.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

A TV studio has brought in 8 boy kittens and 10 girl kittens for a cat food commercial.

This means that $N = 8 + 10 = 18$

We want 3 boys, so $k = 8$

The director is going to choose 8 of these kittens at random to be in the commercial.

This means that $n = 8$

What is the probability that the director chooses 3 boy kittens and 5 girl kittens?

This is P(X = 3).

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

$P(X = 3) = h(3,18,8,8) = \frac{C_{8,3}*C_{10,5}}{C_{18,8}} = 0.323$

0.323 = 32.3% probability that the director chooses 3 boy kittens and 5 girl kittens.

3 0

3 years ago

If x > 0 and y > 0, where is the point (x, y) located?

Scrat [10]

Given, x > 0, y > 0.
So, the values of x and y are less than 0, that means, they are negative integers.
If we divide a Cartesian plane with the x-axis and y-axis, we get four quadrants.
1st Quadrant : (+,+)
2nd Quadrant : (-,+)
3rd Quadrant : (-,-)
4th Quadrant : (+,-)
Since the values of x and y are both negative, so (x, y) is located in the 3rd Quadrant.

Hope you could get an idea from here.

Doubt clarification - use comment section

8 0

2 years ago

Garfield had $10 in the bank yesterday. Then, Garfield bought dinner for $14, but didn't realize that he overdrew from his bank.

Rudik [331]

I believe it’s 4 since he’s in dept with 4 dollars so that’ll be -4, but the absolute value is 4 since it’s 4 spaces away from 0.

5 0

2 years ago

Can someone helPPPPPPPPPPPPPPPPPP

andrezito [222]

I believe it’s option #3. hopefully that helps :)