Answer:
The third equation: 
Step-by-step explanation:
The two points on the line are
and
.
Slope of the line passing through two points
and
is given as:

Here,
and
are
and
.
Therefore, slope is equal to, 
Now, equation of a straight line with slope m and points
and
is given as:

Now, if we use the 2nd form, then
.
So, the equation is given as :
The answer to the question is 0
Instead, break down the shape into rectangles. Next, calculate the area of both rectangles and add them together. The area of the first rectangle is 72 square centimeters and the area of the second rectangle is 50 square centimeters. Together there are 72 + 50 = 122 square centimeters.
That is how u find a irregular figure..hope this help u
Answer:
200+40+3+0.7+0.09
Step-by-step explanation:
<u>Additional requirements in figure</u> :-
Mark point :-
Draw a straight line from E to AB .
And the point line joins mark it as "F" .
It will generate quadrilateral FBCD.
we get to know In quadrilateral left angle is 90°
How ?
{
proof :
As three angles are given 90° So third angle will also be 90°
Reason:
→ Sum of interior angles = 2 (no. of angles - 2 × 180°
→Sum of interior angles = (4-2 × 180°)
→Sum of interior angles = (2 × 180°)
→Sum of interior angles = 360°
}
<u>✿</u><u>Now let the left angle be </u><u>x</u>
- 90° +90° + 90° + x = 360°
- 180° + 90° + x = 360°
- 270° + x = 360
- x = 360° - 270°
- x = 90°
<u>we know</u> :
Area of rectangle = Length × Breadth
STEPS :
- Area of rectangle = Length × Breadth
- Area of rectangle = 7 × 8
- Area of rectangle = 56 in²
<u>Now let's find EF</u> :
<u>To find A</u>
<u>F</u> :
<u>In triangle AFE</u>:
- EF is base of triangle
- A•F is height of triangle
We know :
<u>Area of triangle =(</u><u> </u><u>Height</u><u> </u><u>×</u><u> </u><u>Base)/2</u>
Steps :
- Area of triangle = (Height × Base)/2
- Area of triangle = (4 × 3)/2
- Area of triangle = 12/2
- Area of triangle = 6 in²
<u>To find area of figure</u> :
- Area of figure = Area of rectangle + Area of triangle
- Area of figure = 56 + 6
- Area of figure = 62 in²
______________________
~WindyMint