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nalin [4]
3 years ago
6

Give an example of each of the following or explain why you think such a set could not exist.

Mathematics
1 answer:
Oksanka [162]3 years ago
6 0

Answer:

a.No

b.No

c.No

Step-by-step explanation:

a.No,Such set does not exist .A set of natural numbers is N

Every point of this set is an isolated point but no accumulation point

Accumulation point:It is defined as that point a of set Swhich every neighborhood contains infinitely many distinct point of set

(a-\epsilon,e+\epsilon)\cap S-{a}\neq\phi

Isolated point : it is defined as that point a of set S which neighborhood   does not contain any other point of set except itself

(a-\epsilon0,a+\epsilon)\cap S-{a}=\phi

Interior point of set :Let a\in S .Then a is called interior point of set when its neighborhood is a subset of set S.

a\in(a-\epsilon,e+\epsilon)\subset S

When a set is uncountable then interior point exist it is  necessary for interior points existance .

Boundary points :Let a\in S .If every non empty neighborhood of a  intersect S and complement of S.

Every member of  a set is a boundary point

b.No, such set does not exist .A non empty set with isolated point then the set have no interior points .By definition of interior point and isolated point .For example.set of natural numbers

c.No, Such set does not exist ,for example set of natural every point is an isolated point and boundary point.By definition of  boundary point and isolated point

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Answer:

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Step-by-step explanation:

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Slope of the line passing through two points (x_{1},y_{1}) and (x_{2},y_{2}) is given as:

m=(y_{2} -y_{1})/ (x_{2} -x_{1})

Here, (x_{1},y_{1}) and (x_{2},y_{2}) are (-1,4) and (1,-2).

Therefore, slope is equal to, m=(-2-4 )/ (1-(-1)

                                               m=-6/2

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Now, equation of a straight line with slope m and points (x_{1},y_{1}) and (x_{2},y_{2}) is given as:

y-y_{1}=m(x-x_{1})\\y-y_{2}=m(x-x_{2})

Now, if we use the 2nd form, then x_{2}=1,y_{2}=-2.

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y-(-2)=-3(x-1)\\y+2=-3(x-1)

                                                 

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Instead, break down the shape into rectangles. Next, calculate the area of both rectangles and add them together. The area of the first rectangle is 72 square centimeters and the area of the second rectangle is 50 square centimeters. Together there are 72 + 50 = 122 square centimeters.

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Step-by-step explanation:

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Find the area. Round to the nearest hundredth when necessary. Be sure you are showing all work to find each figure.
eimsori [14]

<u>Additional requirements in figure</u> :-

Mark point :-

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  • B
  • C
  • D
  • E

Draw a straight line from E to AB .

And the point line joins mark it as "F" .

It will generate quadrilateral FBCD.

we get to know In quadrilateral left angle is 90°

How ?

{

proof :

As three angles are given 90° So third angle will also be 90°

Reason:

→ Sum of interior angles = 2 (no. of angles - 2 × 180°

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}

<u>✿</u><u>Now let the left angle be </u><u>x</u>

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<u>we know</u> :

Area of rectangle = Length × Breadth

STEPS :

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<u>Now let's find EF</u> :

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<u>F</u> :

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<u>In triangle AFE</u>:

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We know :

<u>Area of triangle =(</u><u> </u><u>Height</u><u> </u><u>×</u><u> </u><u>Base)/2</u>

Steps :

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<u>To find area of figure</u> :

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______________________

~WindyMint

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