It is 639.5. this is how you round numbers to the nearest tenth:

if the digit in the hundredths place is 5 or more you round up one, if it is lower than 5 it stays the same, pay no attention to the thousandths place....ex--> 0.497
the 4 is the tenths place
th 9 is the hundredths place
the 7 is the thousandths place......since 9 is 5 or more you round the 4 up one number, so the 4 would be a 5. pay no attention to the 7. lets do another

0.426
the 4 stays as a 4 because 2 is a lower number than 5.

7 0

3 years ago

There are 500 students in a highschool senior class

Bogdan [553]

Answer:

250+250 split

Step-by-step explanation:

3 0

4 years ago

All 6 members of a family work. Their hourly wages (in dollars) are the following.37, 38, 39, 40, 39, 11Assuming that these wage

tiny-mole [99]

We have a sample that in fact represents the population.

We have to calculate the standard deviation of this population.

The difference between the standard deviation of a population comparing it to the calculation of the standard deviation of a sample is that we divide by the population side n instead of (n-1).

We have to start by calculating the mean of the population first:

$\begin{gathered} \mu=\dfrac{1}{n}\sum ^n_{i=1}\, x_i \\ \mu=\dfrac{1}{6}(37+38+39+40+39+11) \\ \mu=\dfrac{204}{6} \\ \mu=34 \end{gathered}$

Now, we can calculate the standard deviation as:

$\sigma=\sqrt[]{\dfrac{1}{n}\sum^n_{i=1}\, (x_i-\mu)^2}$ $\begin{gathered} \sigma=\sqrt[]{\dfrac{1}{6}((37-34)^2+(38-34)^2+(39-34)^2+(40-34)^2+(39-34)^2+(11-34)^2)} \\ \sigma=\sqrt[]{\frac{1}{6}(3^2+4^2+5^2+6^2+5^2+(-23)^2)} \\ \sigma=\sqrt[]{\frac{1}{6}(9+16+25+36+25+529)} \\ \sigma=\sqrt[]{\frac{1}{6}(640)} \\ \sigma\approx\sqrt[]{106.67} \\ \sigma\approx10.33 \end{gathered}$

Answer: the standard deviation of this population is approximately 10.33

3 0

2 years ago

Can someone help me with this equation n-6/3=-4

pentagon [3]

Siplify
6/3=2
so
n-2=-4
ad 2 to both sides
n+2-2=-4+2
n+0=-2
n=-2

8 0

3 years ago