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3 years ago

How many grams of silver bromide could dissolve in one liter of 0.350 molar sodium thiosulfate solution?

1 answer:

fomenos3 years ago

4 0

The reacting equation of the reaction is as follows
AgBr (S) + 2 Na2S2O3 ----> Na3Ag(S2O3) + NaBr

the moles of Na2S203= 0.350 x 1l= 0.350moles
by use of reacting ratio AgBr to Na2S2O3 which is 1:2
therefore the moles of AgBr = 0.350/2=0.175moles
mass is hence= moles x molar mass of AgBr
0.175 x187.8=32.865g

You might be interested in

What effect will increased pressure have on 4A (g) + 5B (g) ---> 2C (g) + 7D (g)

Pie

Answer:

Option a. no change

Explanation:

The question makes sense only if the equation is an equilibrium reaction:

4A (g) + 5B (g) ⇄ 2C (g) + 7D (g)

This is, A and B react to produce C and D, forward reaction; and C and D react to form A and B, reverse reaction.

Then, you can study the effect of increased pressure using LeChatelier's principle.

To counteract the disturbing effect produced by increased pressure on the equilibrium, the system will react shifting the toward to the side where the pressure could be decreased.

That would be toward the side that has less gas molecules.

Since both sides have 9 molecules (4 + 5 = 2 + 7 = 9), the equilibrium concetrations will not change.

That is represented by the first choice: no change.

7 0

4 years ago

The first-order isomerization reaction: cyclopropane → propene has a rate constant of 1.10×10-4 s-1 at 470°C and 5.70×10-4 s-1 a

BigorU [14]

Answer:

Activation energy, Ea, for the reaction 261.7 kj/mole

Explanation:

Given

Rate constant at 470 ⁰C (K₁) = 1.10 x 10⁻⁴ s⁻¹ and rate constant at 500⁰C (K₂) = 5.7 x 10⁻⁴ s⁻¹

Temperature (T₁) = 470 + 273 = 743 K and

temperature (T₂) = 500 + 273 = 773 K

Activation energy (Eₐ) = ?

Universal gas constant (R) = 8.314 J. K⁻¹. mole⁻¹

We know log $\frac{K_{2} }{K_{1} }$ = $\frac{E_{a} }{2.303XR}$ $\frac{(T_{2}-T_{1} ) }{T_{2}T_{1} }$

⇒ log $\frac{5.7 X 10^{-4} }{1.1 X 10^{-4} }$ = $\frac{E_{a} }{2.303X8.314}$ $\frac{(773 - 743)}{773X743}$

⇒ 0.714 = $\frac{E_{a}X30 }{10996950.3}$

⇒ Eₐ = $\frac{7851822.5}{30}$ j/mole = 261.7 Kj/mole

5 0

3 years ago

A chemistry instructor provides each student with 8 test tubes at the beginning of the year. If there are 28 students per class,

Ann [662]

Answer :8*28=224
224*3=672

7 0

4 years ago

NaCl + AgNO3 —> AgCl + NaNO3

Anit [1.1K]

Answer is: 226,88 grams of AgNO₃ is consumed.
Chemical reaction: NaCl + AgNO₃ → AgCl + NaNO₃.
m(NaCl) = 78 g.
n(NaCl) = m(NaCl) ÷ M(NaCl).
n(NaCl) = 78 g ÷ 58,4 g/mol.
n(NaCl) = 1,335 mol.
From chemical reaction: n(NaCl) : n(AgNO₃) = 1 : 1.
n(AgNO₃) = 1,335 mol.
m(AgNO₃) = 1,335 mol · 169,87 g/mol.
m(AgNO₃) = 226,88 g.

5 0

3 years ago

All oxygen atoms have eight protons, and most have eight neutrons as well. What is the mass number of an oxygen isotope that has

denis-greek [22]

Answer: The mass number of an oxygen isotope that has nine neutrons is 17 and isotope is called as Oxygen-17.

Explanation:

Atomic number is defined as the number of protons or number of electrons that are present in an atom.

For a neutral atom:

Atomic number = Number of electrons = Number of proton

Atomic number= Number of protons = 8

Mass number is defined as the sum of number of protons and neutrons that are present in an atom.

Mass number = Number of protons + Number of neutrons

Given: Number of neutrons = 9

Thus mass number = Number of protons + Number of neutrons = 8 + 9 = 17.

Isotopes are elements which have same atomic number but different mass number.

Thus the mass number of an oxygen isotope that has nine neutrons is 17 and isotope is called as Oxygen-17.

5 0

4 years ago