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3 years ago

NaCl + AgNO3 —> AgCl + NaNO3

1 answer:

5 0

Answer is: 226,88 grams of AgNO₃ is consumed.<span>
Chemical reaction: NaCl + AgNO</span>₃ → AgCl + NaNO₃.
<span>m(NaCl) = 78 g.
n</span>(NaCl) = m(NaCl) ÷ M(NaCl).
n(NaCl) = 78 g ÷ 58,4 g/mol.
n(NaCl) = 1,335 mol.
From chemical reaction: n(NaCl) : n(AgNO₃) = 1 : 1.
n(AgNO₃) = 1,335 mol.
m(AgNO₃) = 1,335 mol · 169,87 g/mol.
m(AgNO₃) = 226,88 g.

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If helium effuses through a porous barrier in 1.34 min, how much time (in min) would it take the same amount of ammonia to effus

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