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skad [1K]
3 years ago
12

Phenolphthalein is pink in an aqueous solution having a ph of

Chemistry
1 answer:
strojnjashka [21]3 years ago
4 0

Answer : Phenolphthalein is pink in an aqueous solution having a ph of 12.

Explanation :

Phenolphthalein is an acid-base indicator. It is a colorless solution which remains colorless in acidic solution and changes to pink in basic solution.

An acidic solution has a pH of less than 7 whereas a basic solution has a pH of greater than 7.

The pH transition range for phenolphthalein is between 8-10. Than means when the pH is greater than 8, the color of the solution starts to change.

Among the given options, the only option that shows a basic solution is option (4) . Therefore we can say that phenolphthalein would be pink in a solution having a pH of 12.

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In one process, 6.05 kg of caf2 is treated with an excess of h2so4 and yields 2.85 kg of hf. calculate the percent yield of hf.
Kobotan [32]
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calculation

% yield =  actual mass/ theoretical mass  x100
actual mass = 2.85 Kg

calculate the theoretical  mass
by first  write the equation for reaction

CaF2  +H2SO4  → 2HF  + CaSO4
find  the  moles  of CaF2  used
moles = mass/molar mass
mass = 6.05Kg   = 6.05 x1000 =6050 Kg
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moles= 6050/ 78 = 77.6 moles

by  use  of mole ratio between  CaF2  to HF  which  is  1:2 the  moles of HF is therefore = 77.6 x2 =155.2  moles of Hf

find the  theoretical mass  of HF = moles x  molar mass ( 1 +19=20g/mol)

=   155.2  moles x 20 g/mol = 3104 grams  = 3104 /1000 = 3.104 Kg

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What is the mass of 3.01 x 10^21 atoms of Co
OlgaM077 [116]

Answer:

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General Formulas and Concepts:

<u>Chemistry - Atomic Structure</u>

  • Reading a Periodic Table
  • Using Dimensional Analysis
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

Explanation:

<u>Step 1: Define</u>

3.01 × 10²¹ atoms Co

<u>Step 2: Identify Conversions</u>

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<u>Step 3: Convert</u>

<u />3.01 \cdot 10^{21} \ atoms \ Co(\frac{1 \ mol \ Co}{6.022 \cdot 10^{23} \ atoms \ Co} )(\frac{58.93 \ g \ Co}{1 \ mol \ Co} ) = 0.294552 g Co

<u>Step 4: Check</u>

<em>We are given 3 sig figs. Follow sig fig rules and round.</em>

0.294552 g Co ≈ 0.295 g Co

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