1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
skad [1K]
3 years ago
12

Phenolphthalein is pink in an aqueous solution having a ph of

Chemistry
1 answer:
strojnjashka [21]3 years ago
4 0

Answer : Phenolphthalein is pink in an aqueous solution having a ph of 12.

Explanation :

Phenolphthalein is an acid-base indicator. It is a colorless solution which remains colorless in acidic solution and changes to pink in basic solution.

An acidic solution has a pH of less than 7 whereas a basic solution has a pH of greater than 7.

The pH transition range for phenolphthalein is between 8-10. Than means when the pH is greater than 8, the color of the solution starts to change.

Among the given options, the only option that shows a basic solution is option (4) . Therefore we can say that phenolphthalein would be pink in a solution having a pH of 12.

You might be interested in
When mixed, solutions of silver nitrate, AgNO3, and sodium sulfate, Na2SO4, form a precipitate of silver sulfate, Ag2SO4. The ba
Maslowich

Answer:

2 AgNO3 + Na2SO4 → Ag2SO4 + 2 NaNO3

Explanation:

The general schemefor a reaction is given as;

Reactants --> Products

In this question, the reactants are AgNO3 and Na2SO4. The product is Ag2SO4.

The equation is given as;

AgNO3 + Na2SO4 --> Ag2SO4

The other poduct formed in this reaction is NaNO3.

The full reaction is given as;

AgNO3 + Na2SO4 --> Ag2SO4 + NaNO3

The above reaction is not balanced because there are unequal number of atoms of the elements on both sides of the reaction.

The balanced equation is given as;

2 AgNO3 + Na2SO4 → Ag2SO4 + 2 NaNO3

In this equation, there are equal number of moles of the atoms on both sides.

3 0
3 years ago
Four moles of Argon gas are at a pressure of 1.90 atm, and the temperature is 50 degrees C. What is the volume of the gas?
soldier1979 [14.2K]
N = 4 moles of Ar2, P = 1.90 atm, V = ?
T = 50C = 273 + 50K = 323K
PV = nRT --> V = nRT/P
V = (4)(.0821)(323)/1.90
V = 106.07/ 1.9
V = 55.8 L
4 0
3 years ago
If 0.35 moles of kcl was dissolved in enough water to make 0.2 L of solution, what is molarity?
Mars2501 [29]

Answer:

1.75M

Explanation:

molarity = number of moles of solute/ number of L of solution =

=0.35 mol/0.2L = 1.75 mol/L = 1.75 M

8 0
3 years ago
What part of the sun do we see from earth?
NISA [10]

Answer:

photosphere

Explanation:

photosphere

There are 3 main layers of the Sun that we can see. They are the photosphere, the chromosphere and the corona. Together they make up the "atmosphere" of the Sun. The part of the Sun that glows (and that we see with the naked eye) is called the photosphere

8 0
4 years ago
Read 2 more answers
What describes a change in velocity?
siniylev [52]
Acceleration can be described as changes in speed, changes in direction, or changes in both. Acceleration is a vector.
4 0
3 years ago
Read 2 more answers
Other questions:
  • Which element forms compounds which are involved in smog and acid rain?
    14·2 answers
  • A) 2Fe(s) + O2(g) =>
    11·1 answer
  • How many liters of H2 are required to form 5 moles of H2O at STP?
    7·1 answer
  • According to the following reaction, how many grams of hydrofluoric acid will be formed upon the complete reaction of 25.6 grams
    14·1 answer
  • Based on VSEPR theory and your observations from the Molecular Geometry lab consider the following questions What is the predict
    11·1 answer
  • Explain three factors that can affect the size of a line in a spectrum.
    8·1 answer
  • 29. What is E for a system which has the following two steps:
    12·1 answer
  • What is the atomic radius
    15·1 answer
  • Which of the following statements is NOT
    10·1 answer
  • What should go in the blanks?
    9·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!