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dangina [55]
3 years ago
6

What effect will increased pressure have on 4A (g) + 5B (g) ---> 2C (g) + 7D (g) 

Chemistry
1 answer:
Pie3 years ago
7 0

Answer:

  • <em><u>Option a. no change</u></em>

Explanation:

The question makes sense only if the equation is an equilibrium reaction:

  • <em>4A (g) + 5B (g) ⇄ 2C (g) + 7D (g) </em>

This is, A and B react to produce C and D, forward reaction; and C and D react to form A and B, reverse reaction.

Then, you can study the effect of increased pressure using LeChatelier's principle.

To counteract the disturbing effect produced by increased pressure on the equilibrium, the system will react shifting the toward to the side where the pressure could be decreased.

That would be toward the side that has less gas molecules.

Since both sides have 9 molecules (4 + 5 = 2 + 7 = 9), the equilibrium concetrations will not change.

That is represented by the first choice: no change.

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Sulfur dioxide and oxygen react to form sulfur trioxide during one of the key steps in sulfuric acid synthesis. An industrial ch
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Answer:

Explanation:

From the given information:

The equation for the reaction can be represented as:

2SO_2 + O_2 \to 2SO_3

The I.C.E table can be represented as:

                     2SO₂              O₂                   2SO₃

Initial:             14                  2.6                     0

Change:        -2x                -x                      +2x

Equilibrium:   14 - 2x          2.6 - x                2x

However, Since the amount of sulfur trioxide gas to be 1.6 mol.

SO₃ = 2x,

then x = 1.6/2

x = 0.8 mol

For 2SO₂; we have 14 - 2x

= 14 - 2(0.8)

= 14 - 1.6

= 12.4 mol

For O₂; we have 2.6 - x

= 2.6 - 1.6

= 1.0 mol

Thus;

[SO₂] = moles / volume = ( 12.4/50) = 0.248 M ,

[O₂] = 1/50 = 0.02 M ,  

[SO₃] = 1.6/50 = 0.032 M

Kc = [SO₃]² / [SO₂]² [O₂]

= ( 0.032²) / ( 0.248² x 0.02)

= 0.8325

Recall that; the equilibrium constant for the reaction 2SO_2 + O_2 \to 2SO_3 = 0.8325;

If we want to find:

SO_2 + \dfrac{1}{2}O_2 \to SO_3

Then:

K_c = (0.8325)^{1/2}

\mathbf{K_c = 0.912}

Since no temperature is given to use in the question, it will be impossible to find the final temperature of the mixture.

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3 years ago
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Answer:

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.

.

..,,,,,

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Answer:

The figure is a molecule and a compound

Explanation:

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During a reaction 24 cubic cm of carbon dioxide was given off. After 8 minutes no more gas was produced and the reaction was com
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Answer:

Explanation:

Given parameters:

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Unknown:

rate of reaction

Soution

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In this reaction, 3cm³ of carbon dioxide were produced per minute

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