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3 years ago

14

suppose you have three consecutive integers. The greatest of the three integers is twice as great as the sum of the first two. W

hat are the integers?

1 answer:

zvonat [6]3 years ago

6 0

Answer:

0,1,2

Step-by-step explanation:

(x+2) = 2((x+1)+(x)

x+2 = 2x+2+2x

x+2 = 4x+2

-x -x

2 = 3x + 2

-2 -2

0/3 = 3x/3

0 = x

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Zielflug [23.3K]

Answer:

x = 4
WX = WY = 25
XY = 17

Step-by-step explanation:

The triangle is isosceles with side WX equal to side WY:

WX = WY

9x -11 = 7x -3

2x = 8 . . . . . add 11-7x

x = 4

Then the side measures are ...

WX = WY = 7(4) -3 = 28 -3 = 25

XY = 4(4) +1 = 16 +1 = 17

5 0

3 years ago

16 more than s is at most −80.

polet [3.4K]

Answer:

s + 16 ≤ −80

Step-by-step explanation:

Analyze each part in the word equation:

"16 more than s" s increased by 16; s + 16

"is at most" is equal to or less than; ≤

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Put the equation back together:

s + 16 ≤ −80

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4 years ago

Seclate all the numbers that are solutions to the inequalitt w>1.

natima [27]

Answer:

The numbers should be A. 5 and C. 0.

Hope I Helped

6 0

3 years ago

Read 2 more answers

-15=-4m+5<br><br>8n+7=31<br><br>-10=10(k-9)

Korolek [52]

$-15=-4m+5\ \ \ |both\ sides\ /+4m\\\\4m-15=5\ \ \ \ |both\ sides\ /+15\\\\4m=20\ \ \ \ |both\ sides\ /:4\\\\\underline{\underline{m=5}}$

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$8n+7=31\ \ \ \ |both\ sides\ /-7\\\\8n=24\ \ \ \ |both\ sides\ /:8\\\\\underline{\underline{n=3}}$

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$10(k-9)=-10\ \ \ \ |both\ sides\ /:10\\\\k-9=-1\ \ \ \ |both\ sides\ /+9\\\\\underline{\underline{k=8}}$

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klasskru [66]

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