Step-by-step explanation:
ax^2+bx+c=0
a=leading term
ok so if the leading term is positive then opens up and has a <u>min</u>
if leading term is negative then opens down and has a <u>max</u>
leading term is positive
1x^2+8x
it has a min
to complete the square, move c aside take 1/2 of b and square it
b=8
8/2=4
4^2=16
now add that to both sides
x^2+8x+16+6=0+16
factor perfect square
(x+4)^2+6=16
subtract 6
(x+4)^2=10
subtract 10
(x+4)^2-10=0
vertex aka min or max is (h,k) when ou have
y=a(x-h)+k
h=-4
k=-10
D=event that chip selected is defective
d=event that chip selected is NOT defective
Four possible scenarios for the first two selections:
P(DDD)=15/100*14/99*13/98=13/4620
P(DdD)=15/100*85/99*14/98=17/924
P(dDD)=85/100*15/99*14/99=17/924
P(ddD)=85/100*84/99*15/98=17/154
Probability of third selection being defective is the sum of all cases,
P(XXD)=P(DDD)+P(DdD)+P(dDD)+P(ddD)
=3/20
Answer:
6r + 7 = 13 + 7r
subtract 6r from both sides...
7 = 13 + r
subtract 13 from both sides...
-6 = r
r = -6
Step-by-step explanation:
