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3 years ago

Why did I get this question wrong?

Mathematics

1 answer:

lord [1]3 years ago

4 0

Step-by-step explanation:

∫₀³⁰ (r/V C₀ e^(-rt/V)) dt

If u = -rt/V, then du = -r/V dt.

∫ -C₀ e^u du

-C₀ ∫ e^u du

-C₀ e^u + C

-C₀ e^(-rt/V) + C

Evaluate between t=0 and t=30.

-C₀ e^(-30r/V) − -C₀ e^(-0r/V)

-C₀ e^(-30r/V) + C₀

C₀ (-e^(-30r/V) + 1)

I got the same answer. Try changing the lowercase v to an uppercase V.

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Arturo, Pedro y Jorge son hermanos y duermen en la misma habitación. Su padre compró pintura para que entre los tres pinten su c

mr Goodwill [35]

Answer:

Tanto Pedro como Jorge deberán pintar 1/4 de la habitación cada uno.

Step-by-step explanation:

Dado que el cuarto entero es igual a 1, y que Arturo por ser el mayor de los hermanos tiene que pintar 1/2 de él, la parte que falta pintar es igual a 1/2 restante.

De ese 1/2, los hermanos menores, Pedro y Jorge, deben pintar dicha fracción en partes iguales. Por lo tanto, dado que (1/2) / 2 es igual a 1/4, la fracción que tanto Pedro como Jorge deberán pintar es de 1/4 de la habitación.

4 0

3 years ago

Read 2 more answers

What is the nth term of the sequence -2 -8 -18 -32 -50

andreev551 [17]

Answer:

-2n²

Step-by-step explanation:

Using the image attached:
We see that the second differences (blue ones) are all equal so we conclude that this is a quadratic sequence.
The quadratic sequence has the form:
$T_{n} = an^{2} +bn +c$

To find the value of a we just divide second difference ( -4 ) by 2:

$a = \frac{-4}{2}= -2$

Now we have:

$T_{n}= -2n^{2} +bn+c$

Substitute $n_{1}$ and $n_{2}$ into the equation above:

$T_{1} = -2(1)^{2} +b(1) +c$

$T_{2} = -2(2)^{2} +b(2)+c$

Since $T_{1}$ = -2 and $T_{2}$ = -8 , after simplification we have:

$b +c =0$
$2b+c=0$

The solution of this system is:

b=0, c =0

The general term is :

$T_{n} = -2n^{2}$

6 0

2 years ago

Using scientific notation, what is the solution to (2.82 * 104) * (3.1 * 103)?

MArishka [77]

Answer: Choice A) 8.742 * 10^7

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Work Shown:

$(a * 10^b) \times (c * 10^d) = a*c*10^{b+d}\\\\(2.82 * 10^4) \times (3.1 * 10^3) = 2.82*3.1*10^{4+3}\\\\(2.82 * 10^4) \times (3.1 * 10^3) = 8.742*10^{7}\\\\$