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vekshin1
3 years ago
8

A raindrops has a mass of 0.50g. how many moles of water does a raindrop contain

Mathematics
1 answer:
alina1380 [7]3 years ago
7 0
So, here you have to look at the periodic table and see what the molar mass of each molecule composing the water compound H_2 O
its two hydrogen atom plus an oxygen molecule, making it about 18g per mol.

That said, looking at the mass, we have to ask ourselves, if a mol of water contains 18g of mass, how many moles do we have in 0.5g of water? 
We just do a cross multiplication:
\frac{(0.5)}{18} =0.027 mol
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mr_godi [17]

The x-intercepts and the y-intercepts of the function is that determines the graph is:

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  • y-intercepts = (0,2)

<h3>How do we graph the function y = f(x) of an absolute equation?</h3>

The function of an absolute equation can be graphed by determining the values of x-intercepts and the y-intercepts of the function.

From the given equation:

y = 2|x+3| - 4

To determine the y-intercepts, we need to set the values of x to zero, and vice versa for x-intercepts.

By doing so, the x-intercepts and the y-intercepts of the function is:

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Therefore, since we know the x and y-intercepts, the graph of the absolute value can be seen as plotted below.

Learn more about determining the graph of an absolute equation here:

brainly.com/question/2166748

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8 0
1 year ago
If y varies directly as x and y = 144 when x = 12, what is the value of y when x = 17?
olasank [31]
Direct variation:
y=kx

y=144 when x=12.
144=12k \\ k=\frac{144}{12} \\ k=12

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6 0
3 years ago
Suppose the sediment density (g/cm3 ) of a randomly selected specimen from a certain region is known to have a mean of 2.80 and
Irina18 [472]

Answer:

0.918 is the probability that the sample average sediment density is at most 3.00

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 2.80

Standard Deviation, σ = 0.85

Sample size,n = 35

We are given that the distribution of sediment density is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

Standard error due to sampling:

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P( x \leq 3.00) = P( z \leq \displaystyle\frac{3.00 - 2.80}{0.1437}) = P(z \leq 1.3917)

Calculation the value from standard normal z table, we have,  

P(x \leq 3.00) = 0.918

0.918 is the probability that the sample average sediment density is at most 3.00

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