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3 years ago

You are attempting to estimate the number of protester marching through the city

Mathematics

1 answer:

Alenkinab [10]3 years ago

3 0

9514 1404 393

Answer:

1000

Step-by-step explanation:

If the number of protesters per minute remains a constant, then you could write the proportion ...

p/12 = 177/2.1

Multiplying by 12 gives ...

p = 12(177/2.1) ≈ 1011.4

Here, minutes are given to 2 significant figures, and the initial count is given to 3 significant figures. The best you can hope for is that your estimate is good to 3 significant figures:

1010 protesters

It is probably sufficient to report the number to 2 significant figures*:

1000 protesters

_____

* Unfortunately, with a number like 1000, the only way you can tell it has 2 significant figures is to report it as 1.0×10³ or 10. hundreds. The trailing zeros are usually not considered significant.

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Rob borrows $15.00 from his father, and then he borrows $3.00 more. Drag numbers to write an equation using negative integers to

Paul [167]

Answer:

Rob owes his father=-$15-$3= -$18

Step-by-step explanation:

Rob borrows $15 first and then $3.

Since we have to use negative integers, so

-$15-$3= -$18

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3 years ago

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X/5+ 7 = y Solve for x<br> pls hurry

Setler [38]

Answer:

x=5y-35

Step-by-step explanation:

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3 years ago

People tend to evaluate the quality of their lives relative to others around them (Frieswijk et al., 2004). In one study, resear

Alborosie

Answer:

Step-by-step explanation:

Hello!

Research.

n=9 frail elderly were interview and compared to a fictitious person who was worse off then the interviewee, a life-satisfaction score was determined for each person.

18, 23, 24, 22, 19, 27, 23, 26, 25

Assuming that the population average score is μ= 20, the researchers think that the elderly in the sample are more or less satisfied than others in the general population.

a. You have the information of one sample, assuming this sample has a normal distribution and each elderly interviewed is independent, then the t-test of choice is a one-sample t-test.

b. and c. If you say that the elderly are "more or less" satisfied than the others, this means that they are either as satisfied as to the general population or not satisfied as to the general population. Symbolically:

H₀: μ = 20

H₁: μ ≠ 20

This is a two-tailed test, meaning, you will have two critical regions.

α: 0.05

Left critical value: $t_{n-1;/\alpha 2} = t_{8; 0.025}= -2.306$

Right critical value: $t_{n-1;1-\alpha /2} = t_{8;0.975} = 2.306$

$t_{H_0}= \frac{X[bar]-Mu}{\frac{S}{\sqrt{n} } } ~t_{n-1}$

X[bar]= 23

S= 3

$t_{H_0}= \frac{23-20}{\frac{3}{\sqrt{9} } }= 3$

Considering that the calculated t-value is greater than the right critical value, the decision is to reject the null hypothesis, so using a significance level of 5% you can conclude that the average life-satisfaction score of the elderly is different than 20.

I hope it helps!

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3 years ago

Use the x-intercept method to find all real solutions of the equation -9^3-72^2-96x+36=3x^3+x^2-3x+8

Vadim26 [7]

Answer:

x ≈ 0.290640965127

Step-by-step explanation:

y subtracting the right side of the equation, we get a function that is zero at a real solution for x. The only x-intercept is at approximately 0.290640965127.

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The graph shows the x-intercept to be 0.2906. The value above was obtained by Newton's method iteration. The roots of this cubic will all be irrational.

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3 years ago

PLEASE HELP 17 points

Ksivusya [100]

Answer: I say B its a bit hard but i think i got it not sure but Good Luck!

Step-by-step explanation:

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3 years ago

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