What is the equation of this graph?

Write the equation of a line in standard form that has x-intercept (P,0) and y-intercept (0,R).

ExtremeBDS [4]

Answer:

$Rx+Py=RP$

Step-by-step explanation:

The points on the straight line are (P, 0) and (0, R).

The slope would be

$m=\frac{R-0}{0-P}=-\frac{R}{P}$

And $b=R$ , because the y-intercept is at (0, R).

So, the equation of this line would be

$y=-\frac{R}{P} x+R$

Where we multiply the equation by $P$

$Py=-Rx+RP$

Therefore, the equation that represents this line is

$Rx+Py=RP$

<h2>So, the right answer is B.</h2>

7 0

3 years ago

Help Me Pls Thanks <3

dybincka [34]

If there are 150 total instruments in said Orchestra, we'll need to divide that number in half.
75, simple enough. Now we know that half of 150 is 75.
Start by writing your problem like this: 150= 75w+37.5b
That equation is all I can think of, because 37.5 is half of 75, which means that's roughly the number you're looking for. Sorry if this doesn't help much<span />

8 0

3 years ago

3. For the polynomial: ()=−2(+19)3(−14)(+3)2, do the following:A. Create a table of values that have the x-intercepts of p(x) in

Pepsi [2]

Part A. We are given the following polynomial:

$\mleft(\mright)=-2\mleft(+19\mright)^3\mleft(-14\mright)\mleft(+3\mright)^2$

This is a polynomial of the form:

$p=k(x-a)^b(x-c)^d\ldots(x-e)^f$

The x-intercepts are the numbers that make the polynomial zero, that is:

$\begin{gathered} p=0 \\ (x-a)^b(x-c)^d\ldots(x-e)^f=0 \end{gathered}$

The values of x are then found by setting each factor to zero:

$\begin{gathered} (x-a)=0 \\ (x-c)=0 \\ \text{.} \\ \text{.} \\ (x-e)=0 \end{gathered}$

Therefore, this values are:

$\begin{gathered} x=a \\ x=c \\ \text{.} \\ \text{.} \\ x=e \end{gathered}$

In this case, the x-intercepts are:

$\begin{gathered} x=-19 \\ x=14 \\ x=-3 \end{gathered}$

The multiplicity are the exponents of the factor where we got the x-intercept, therefore, the multiplicities are:

Part B. The degree of a polynomial is the sum of its multiplicities, therefore, the degree in this case is:

$\begin{gathered} n=3+1+2 \\ n=6 \end{gathered}$

To determine the end behavior of the polynomial we need to know the sign of the leading coefficient that is, the sign of the coefficient of the term with the highest power. In this case, the leading coefficient is -2, since the degree of the polynomial is an even number this means that both ends are down. If the leading coefficient were a positive number then both ends would go up. In the case that the leading coefficient was positive and the degree and odd number then the left end would be down and the right end would be up, and if the leading coefficient were a negative number and the degree an odd number then the left end would be up and the right end would be down.

Part C. A sketch of the graph is the following:

If the multiplicity is an odd number the graph will cross the x-axis at that x-intercept and if the multiplicity is an even number it will tangent to the x-axis at that x-intercept.