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4 years ago

Please explain this, I have no idea how to do it!

Mathematics

2 answers:

Art [367]4 years ago

8 0

Answer:

t=40.5

Step-by-step explanation:

T likely stands for time. but I suspect you haven't given us the full question because the piece you gave us doesn't determine what T stands for. either way, t is your variable. could be substituted for x or any other variable.

t2=81

isolate t

t= 81/2

t= 40.5

inn [45]4 years ago

7 0

Answer:

t = 9

Step-by-step explanation:

t² = 81

√t² = √81

t = 9

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Answer:

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Step-by-step explanation:

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3 years ago

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Helen drove from the restaurant to the toy store, which

Morgarella [4.7K]

Answer:

4,3

Step-by-step explanation:

4,3

6 0

4 years ago

This is multiplying fractions and i have to show work

grandymaker [24]

To solve:

$\frac{2}{3}\times(-4\frac{1}{3})$

Let us convert the mixed fraction into fraction first,

$\frac{2}{3}\times(-\frac{13}{3})$

On simplification we get,

$-\frac{26}{9}$

Hence, the answer is,

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7 0

1 year ago

(2x+3)(4x-1)<8x^(2)+1

Sidana [21]

Answer: $x$

Step-by-step explanation:

$(2x+3)(4x-1)$

Begin by multiplying parentheses.

$(2x*4x)+(2x*-1)+(3*4x)+(3*-1)$

$(8x^2)+(-2x)+(12x)+(-3)$

$8x^2-2x+12x-3$

Subtract $8x^2$

$8x^2-2x+12x-3+(-8x^2)$

$-2x+12x-3$

Add 3

$-2x+12x-3+3$

$-2x+12x$

Combine like terms;

$10x$

Divide by 10

$x$

Simplify;

$x$

8 0

3 years ago

The table shows the number of toys sold at Penelope's Toys and Games store in different years. Find the rate of change in the nu

Aliun [14]

Answer:

Year - (1993 - 1995)

Step-by-step explanation:

Rate of change in the number of toys sold = $\frac{\text{change in number of toys sold}}{\text{Time interval}}$

In the interval (1990 - 1993),

Rate of change in number of toys sold = $\frac{32000-20000}{1993-1990}$

= $\frac{12000}{3}$

= 4000

In the interval (1993 - 1995),

Rate of change = $\frac{42000-32000}{1995-1993}$

= $\frac{10000}{2}$

= 5000

In the interval (2000 - 1995),

Rate of change = $\frac{57000-42000}{2000-1995}$

= $\frac{15000}{5}$

= 3000

In the interval (2006 - 2000),

Rate of change = $\frac{63000-57000}{2006-2000}$

= $\frac{6000}{6}$

= 1000

Therefore, rate of change in the number of toys sold is greatest in the interval (1993 - 1995).

4 0

3 years ago