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1 year ago

What is 8 - 7x = 1find x

Mathematics

2 answers:

Natali5045456 [20]1 year ago

5 0

Answer:

x=1

Step-by-step explanation:

kvasek [131]1 year ago

5 0

Answer:

x = 1

Step-by-step explanation:

8 - 7x = 1

- 8 - 8

-7x = -7

/-7 /-7

x = 1

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Finish solving the system of equations –9.5x – 2.5y = –4.3 and 7x + 2.5y = 0.8 using the linear combination method. 1. Determine

mars1129 [50]

Answer:

Step-by-step explanation:

The given equations are:

-9.5x – 2.5y = –4.3 (1)

and 7x + 2.5y = 0.8 (2)

Adding equation (1) and (2) together, we get

-9.5x-2.5y+7x+2.5y=-4.3+0.8

⇒-2.5x=-3.5

⇒x=1.4

Now, substitute the value of x=1.4 in equation (1),

-9.5(1.4)-2.5y=-4.3

⇒-13.3-2.5y=-4.3

⇒-13.3+4.3=2.5y

⇒-9=2.5y

⇒y=-3.6

Thus, the value of x and y are 1.4 and -3.6 respectively.

7 0

2 years ago

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The price of a watch was increased by 20% to £144. What was the price before the increase?

hammer [34]

Answer:

120 pounds

Step-by-step explanation:

Since the new cost is 144 pounds and this is 20% more, this is 120% of the original price. Remember 100+20 = 120. To find the original price set up a proportion with these values:

$\frac{144}{x}=\frac{120}{100}$

Solve for the original price by cross multiplying numerator with denominator.

x(120) = 144(100)

120x = 14400

x= 120 pounds

6 0

2 years ago

Two thirds as a decimal

larisa [96]

2/3
=0.6666666... is your final answer. Hope it help!

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2 years ago

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Find the Maclaurin series for f(x) using the definition of a Maclaurin series. [Assume that f has a power series expansion. Do n

aliya0001 [1]

Answer:

$f(x)=\sum_{n=1}^{\infty}(-1)^{(n-1)}2^{n}\dfrac{x^n}{n}$

Step-by-step explanation:

The Maclaurin series of a function f(x) is the Taylor series of the function of the series around zero which is given by

$f(x)=f(0)+f^{\prime}(0)x+f^{\prime \prime}(0)\dfrac{x^2}{2!}+ ...+f^{(n)}(0)\dfrac{x^n}{n!}+...$

We first compute the n-th derivative of $f(x)=\ln(1+2x)$ , note that

$f^{\prime}(x)= 2 \cdot (1+2x)^{-1}\\f^{\prime \prime}(x)= 2^2\cdot (-1) \cdot (1+2x)^{-2}\\f^{\prime \prime}(x)= 2^3\cdot (-1)^2\cdot 2 \cdot (1+2x)^{-3}\\...\\\\f^{n}(x)= 2^n\cdot (-1)^{(n-1)}\cdot (n-1)! \cdot (1+2x)^{-n}\\$

Now, if we compute the n-th derivative at 0 we get

$f(0)=\ln(1+2\cdot 0)=\ln(1)=0\\\\f^{\prime}(0)=2 \cdot 1 =2\\\\f^{(2)}(0)=2^{2}\cdot(-1)\\\\f^{(3)}(0)=2^{3}\cdot (-1)^2\cdot 2\\\\...\\\\f^{(n)}(0)=2^n\cdot(-1)^{(n-1)}\cdot (n-1)!$

and so the Maclaurin series for f(x)=ln(1+2x) is given by

$f(x)=0+2x-2^2\dfrac{x^2}{2!}+2^3\cdot 2! \dfrac{x^3}{3!}+...+(-1)^{(n-1)}(n-1)!\cdot 2^n\dfrac{x^n}{n!}+...\\\\= 0 + 2x -2^2 \dfrac{x^2}{2!}+2^3\dfrac{x^3}{3!}+...+(-1)^{(n-1)}2^{n}\dfrac{x^n}{n}+...\\\\=\sum_{n=1}^{\infty}(-1)^{(n-1)}2^n\dfrac{x^n}{n}$

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2 years ago

Bella has a bag of grapes that weighs 1 3/4 pounds. She wants to divide the grapes into equal shares that each weigh 5/16 pounds

UNO [17]

Answer:

your is 5

Step-by-step explanation:

and make me barinly least

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2 years ago

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What is 8 - 7x = 1find x​

What is 8 - 7x = 1find x