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1 year ago

PLS HELP IM SUPER STUCK AAA

Mathematics

1 answer:

Nana76 [90]1 year ago

4 0

Answer:

(15,0) , (0,6)

Step-by-step explanation:

Same concept as the previous 2 questions.

x-intercept is where the line touches the x-axis, and y = 0.

when y = 0,

12x + 30(0) = 180

12x = 180

x = $\frac{180}{12}$

x = 15

Therefore the coordinates of the x-intercept is (15,0)

y-intercept is where the line touches the y-axis, and x = 0.

when x = 0,

12(0) + 30y = 180

30y = 180

y = $\frac{180}{30}$

y = 6

Therefore the coordinates of the y-intercept is (0,6)

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MariettaO [177]

$\qquad\qquad\huge\underline{{\sf Answer}}$

Let's find out the gradient (Slope " m ") of line q ;

$\qquad \sf \dashrightarrow \:m = \dfrac{y_2 - y_1}{x_2 - x_1}$

$\qquad \sf \dashrightarrow \:m = \dfrac{4 - 0}{0 - 1}$

$\qquad \sf \dashrightarrow \:m = - 4$

Now, since we already know the gradient let's find of the equation of line by using its Slope and one of the points using point slope form of line :

$\qquad \sf \dashrightarrow \:y - 4 = m(x - 0)$

$\qquad \sf \dashrightarrow \:y = mx + 4$

Now, plug in the value of gradient ~

$\qquad \sf \dashrightarrow \:y = - 4x + 4$

here we can clearly observe that, the Area under the curve can easily be represented as :

$\qquad \sf \dashrightarrow \:y < - 4x + 4$

Since, all the values of y that lies in the shaded region is smaller than the actual value of y for the corresponding values of x in the equation of line q

5 0

1 year ago

What of the following functions is graphed below

leva [86]

The correct answer is C

5 0

2 years ago

If you can buy 4 containers of pudding for $4.20 how much can you buy for $9.45 math problem

lyudmila [28]

Answer:

Step-by-step explanation:

4.20 / 4 = 1.05

105 x 9 = 9.45

8 0

2 years ago

A helicopter flew north 325 meters and then flew east 500 meters. How far is the helicopter from its starting point?

kati45 [8]

Answer:

596.34m approx

Step-by-step explanation:

Given data

Let the Starting point be x

A helicopter flew north 325 meters from x

Then flew east 500 meters

Let us apply the Pythagoras theorem to solve for the resultant which is the distance from the starting position

x^2= 325^2+500^2

x^2=105625+250000

x^2= 355625

x= √355625

x=596.34m

Hence the distance from the starting point is 596.34m approx

8 0

2 years ago

HELP PLS! A boat is heading towards a lighthouse, whose beacon-light is 102 feet above the water. From point AA, the boat’s crew

KatRina [158]

Answer:

Distance from point AA to point BB = 189.3 feet

Step-by-step explanation:

Let the distance from point AA to the base of the lighthouse be represented by x, and the distance from point BB to the base of the lighthouse be represented by y. So that;

distance from point AA to point BB = x - y

To determine the value of x, applying the required trigonometric function;

Tan θ = $\frac{opposite}{sdjacent}$