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aleksklad [387]
3 years ago
10

A CI is desired for the true average stray-load loss μ (watts) for a certain type of induction motor when the line current is he

ld at 10 amps for a speed of 1500 rpm. Assume that stray-load loss is normally distributed with σ = 2.3. (Round your answers to two decimal places.)
Mathematics
1 answer:
Stella [2.4K]3 years ago
7 0
Hey sorry babe I’m gonna I’ll call y’all tomorrow and I wanna was a time to take my home and get it and I’ll do my stuff and then go
You might be interested in
What is the inverse of f(x)=2^x
GuDViN [60]

Answer:

<h2>{f}^{ - 1} (x) =  \frac{ln(x)}{ln(2)}</h2>

Step-by-step explanation:

f(x)=2^x

y =  {2}^{x}

x =  {2}^{y}

{2}^{y}  = x

ln( {2}^{y} )=ln(x)

yln(2)=ln(x)

<h3>\frac{yln(2)}{ln(2)}  =  \frac{ln(x)}{ln(2)}</h3><h3>y =  \frac{ln(x)}{ln(2)}</h3><h3>{f}^{ - 1} (x) =  \frac{ln(x)}{ln(2)}</h3><h3>Hope it is helpful...</h3>
3 0
3 years ago
A jug of milk holds 4 quarts. How many liters of milk does the jug hold? Round your answer to the nearest hundredth of a liter.
GuDViN [60]

Answer:

The answer is 3.785, but rounding it to the nearest hundredth is 3.68 or 3.79, depending on rather they wanted you to take the t and round up or just leave it off.

4 0
3 years ago
If U = {all positive integers) and A = {x|x EU and x is an odd positive integer}, which describes AC?
Galina-37 [17]

Answer:

last choice

Step-by-step explanation:

If we are looking at positive integers and we take out the odd ones, the only one's that are left are the even ones.

So last choice.   (Also I assume AC meant the complement of A)

7 0
3 years ago
Read 2 more answers
How do I do this a second way? I totally forgot because I haven't done it in so long.
ira [324]
You take away the 4 from the 8 which is equal to 4 then you have to barrow from the 2 to make the 4 to 14 and when you    wait you are basically right your calculation is right
5 0
3 years ago
6. David gets 65 chocolates an hour for cleaning. He gets a 15% raise. He
Sonja [21]

Answer:

Before raise: 65 chocolates/hour*60=3900 chocolates

Raise=65 * (15%=15/100=.15) .15=9.75 more chocolates per hour

With raise 74.75 chocolates/hour*60=4485 chocolates

4485-3900=585 more chocolates per 60 hour week

Step-by-step explanation:

7 0
1 year ago
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