Answer:
Step-by-step explanation:
Given : In a state where license plates contain six digits.
Probability of that a number is 9 =
[Since total digits = 10]
We assume that each digit of the license number is randomly selected .
Since each digit in the license plate is independent from the other and there is only two possible outcomes for given case (either 9 or not), so we can use Binomial.
Binomial probability formula: 
, where n= total trials , p = probability for each success.
Let x be the number of 9s in the license plate number.

Then, the probability that the license number of a randomly selected car has exactly two 9's will be :

Hence, the required probability = 0.098415
1) (3-x) x (3+x)
2) 5(5-x) x (5+x)
3) (3v-wy) x (3v+wy)
4) 2(k-m) x (k+m) x (k^2+m^2)
5) (ab-4c) x (ab+4c)
Brainliest?
The answer is a because we don’t care