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3 years ago

5

HELP PLEASE IM GOING TO DIE PLEASE

2 answers:

zysi [14]3 years ago

8 0

Answer:

21. 4

Step-by-step explanation:

2*3=6

4*6=24

24/6=4

what is a three band stretches

s2008m [1.1K]3 years ago

3 0

21.4 I looked up and saw it

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ASAP HELP ASAP THANK YOU

aliya0001 [1]

15.6/-3 = - 5.2 is the answer

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3 years ago

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When solving an equation, Tina gets to the last of line of her work and is left with "7=7." What does this mean?

jarptica [38.1K]

Answer:

B , there are infinite solutions.

Step-by-step explanation:

If you end an equation with a true statement, such as 0 = 0, then any value of the variable(s) you are solving for will satisfy the equation. This means that there are infinite solutions.

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3 years ago

Which of the following is a conditional statement?

anyanavicka [17]

A, because it's based on whether or not they do their chores, and it's not for certain

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3 years ago

What is the volume of the figure? PLEASE HELP ASAP NO LINKS

kotykmax [81]

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Step-by-step explanation:

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3 years ago

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1. S(–4, –4), P(4, –2), A(6, 6) and Z(–2, 4) a) Apply the distance formula for each side to determine whether SPAZ is equilatera

Aleksandr [31]

Answer:

a) SPAZ is equilateral.

b) Diagonals SA and PZ are perpendicular to each other.

c) Diagonals SA and PZ bisect each other.

Step-by-step explanation:

At first we form the triangle with the help of a graphing tool and whose result is attached below. It seems to be a paralellogram.

a) If figure is equilateral, then SP = PA = AZ = ZS:

$SP = \sqrt{[4-(-4)]^{2}+[(-2)-(-4)]^{2}}$

$SP \approx 8.246$

$PA = \sqrt{(6-4)^{2}+[6-(-2)]^{2}}$

$PA \approx 8.246$

$AZ =\sqrt{(-2-6)^{2}+(4-6)^{2}}$

$AZ \approx 8.246$

$ZS = \sqrt{[-4-(-2)]^{2}+(-4-4)^{2}}$

$ZS \approx 8.246$

Therefore, SPAZ is equilateral.

b) We use the slope formula to determine the inclination of diagonals SA and PZ:

$m_{SA} = \frac{6-(-4)}{6-(-4)}$

$m_{SA} = 1$

$m_{PZ} = \frac{4-(-2)}{-2-4}$

$m_{PZ} = -1$

Since $m_{SA}\cdot m_{PZ} = -1$ , diagonals SA and PZ are perpendicular to each other.

c) The diagonals bisect each other if and only if both have the same midpoint. Now we proceed to determine the midpoints of each diagonal:

$M_{SA} = \frac{1}{2}\cdot S(x,y) + \frac{1}{2}\cdot A(x,y)$

$M_{SA} = \frac{1}{2}\cdot (-4,-4)+\frac{1}{2}\cdot (6,6)$

$M_{SA} = (-2,-2)+(3,3)$

$M_{SA} = (1,1)$

$M_{PZ} = \frac{1}{2}\cdot P(x,y) + \frac{1}{2}\cdot Z(x,y)$

$M_{PZ} = \frac{1}{2}\cdot (4,-2)+\frac{1}{2}\cdot (-2,4)$

$M_{PZ} = (2,-1)+(-1,2)$

$M_{PZ} = (1,1)$

Then, the diagonals SA and PZ bisect each other.

8 0

3 years ago