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Scrat [10]
3 years ago
11

Special right triangles please help! Find the variable

Mathematics
1 answer:
Ksivusya [100]3 years ago
4 0

Answer:

  11. s = 14

  12. k = 24

Step-by-step explanation:

There are two "special" right triangles that show up in trig and geometry problems.

The isosceles right triangle has angles of 45°-45°-90°, and side length ratios 1 : 1 : √2.

The half-equilateral triangle has angles of 30°-60°-90°, and side length ratios 1 : √3 : 2.

You will do yourself a favor if you remember and learn to recognize these triangles.

__

<h3>11.)</h3>

The hypotenuse of the isosceles right triangle is 14√2. This tells you the basic ratio has been multiplied by 14. The side length is ...

  s = 14

__

<h3>12.)</h3>

The half-equilateral triangle has middle-length side 12√3. This means the basic ratio has been multiplied by 12. The triangle short side is 12, and the long side is twice that:

  k = 24

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a week before election day, 276 out of 450 people said they would vote for the republican candidate. if 15,240 registered voters
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Answer:

(a) \frac {276}{450}=\frac {y}{15240}

(b) We cross multiply the probability by the total voters

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Step-by-step explanation:

(a)

Probability of getting a republican voter is

\frac {276}{450}=\frac {138}{225}=\frac {46}{75}

\frac {276}{450}=\frac {138}{225}=\frac {46}{75}=\frac {y}{15240}

These are found by dividing the first numerator and denominator by 2, then by 3

To make it complete, the situation is therefore defined as \frac {276}{450}=\frac {y}{15240} where y is unknown value

(b)

Cross multiplication of the probability and number of voters gives the actual figure of y in the equation formed in part a of the question.

(c)

Since we have 15240 voters who plan to participate in election, we cross multiply to get the approximate number of republican voters which yields

\frac {46}{75}\times 15240=9347.2\approx 9347

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4 years ago
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Furkat [3]

Answer: x = 3 - sqrt 17 / 2 , x = 3 + sqrt 17 / 2

Step-by-step explanation:

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answer

x = 3 - sqrt 17 / 2 , x = 3 + sqrt 17 / 2

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