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Nataly_w [17]
3 years ago
10

What is the correct name for a 9-sided polygon? decagon octagon nonagon ninagon

Mathematics
2 answers:
defon3 years ago
8 0

Answer:

option c. nonagon

..............

Anni [7]3 years ago
4 0

Answer:

nonagon

Step-by-step explanation:

The correct name for a 9-sided polygon is <u>nonagon</u><u>.</u>

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Which situation can be represented by the equation -20 x 4 = -80
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You owed someone 20 dollars at 4 different times, you owe them 80 dollars in total
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Why does dividing 5 by a decimal less than 1 give a quotient greater than 5
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5 0
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Jacob solves the system of equations by forming a matrix equation.
Lyrx [107]

Simultaneous equations can be solved using inverse matrix operation.

The complete steps of Jacob's solution are:

\left[\begin{array}{cc}4&1\\-2&3\end{array}\right]^{-1} \cdot \left[\begin{array}{cc}4&1\\-2&3\end{array}\right]\left[\begin{array}{c}x&y\end{array}\right] = \frac{1}{14}\left[\begin{array}{cc}3&-1\\2&4\end{array}\right] \cdot \left[\begin{array}{c}2&-22\end{array}\right]

\left[\begin{array}{c}x&y\end{array}\right] = \left[\begin{array}{cc}4&1\\-2&3\end{array}\right] \cdot \left[\begin{array}{c}2&-22\end{array}\right]

\left[\begin{array}{c}x&y\end{array}\right] = \frac{1}{14} \left[\begin{array}{c}28&-84\end{array}\right]

\left[\begin{array}{c}x&y\end{array}\right] = \left[\begin{array}{c}2&-6\end{array}\right]

We have:

4x + y = 2

-2x + 4y = -22

Calculate the determinant of \left[\begin{array}{cc}4&1\\-2&3\end{array}\right]

|A| = 4 \times 3 -1 \times -2

|A| = 12 +2

|A| = 14

So, the inverse matrix becomes

A = \frac{1}{14}\left[\begin{array}{cc}4&1\\-2&3\end{array}\right]

Replace the first column with \left[\begin{array}{c}2&-22\end{array}\right] to calculate the value of x

x = \frac{1}{14}\left[\begin{array}{cc}2&1\\-22&3\end{array}\right]

So, we have:

x = \frac{1}{14}(2 \times 3 - 1 \times -22)

x = \frac{1}{14}(6 +22)

x = \frac{1}{14}(28)

x = 2

Replace the second column with \left[\begin{array}{c}2&-22\end{array}\right] to calculate the value of y

y = \frac{1}{14}\left[\begin{array}{cc}4&2\\-2&-22\end{array}\right]

So, we have:

y = \frac{1}{14}(4 \times -22 - 2 \times -2)

y = \frac{1}{14}(-88 +4)

y = \frac{1}{14}(-84)

y = -6

Hence, the complete process is:

\left[\begin{array}{cc}4&1\\-2&3\end{array}\right]^{-1} \cdot \left[\begin{array}{cc}4&1\\-2&3\end{array}\right]\left[\begin{array}{c}x&y\end{array}\right] = \frac{1}{14}\left[\begin{array}{cc}3&-1\\2&4\end{array}\right] \cdot \left[\begin{array}{c}2&-22\end{array}\right]

\left[\begin{array}{c}x&y\end{array}\right] = \left[\begin{array}{cc}4&1\\-2&3\end{array}\right] \cdot \left[\begin{array}{c}2&-22\end{array}\right]

\left[\begin{array}{c}x&y\end{array}\right] = \frac{1}{14} \left[\begin{array}{c}28&-84\end{array}\right]

\left[\begin{array}{c}x&y\end{array}\right] = \left[\begin{array}{c}2&-6\end{array}\right]

Read more about matrices at:

brainly.com/question/11367104

6 0
3 years ago
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