Can some one pleas help me with this
1 answer:
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Answer:
See attachment
Step-by-step explanation:
We want to graph the following equation:
x-y+1=0
and
3x+2y=12
For the first equation: x-y+1=0
When x=0, we have 0-y+1=0---->y=1
We plot the point (0,1)
When y=0, we have x-0+1=0---->x=-1
We plot (-1,0)
We draw a straight line through these two points to get the graph of this line.
For the second equation: 3x+2y=12
When x=0,y=6. So we plot (0,6)
When y=0, x=4, So we plot (4,0)
We draw another straight line through them to obtain the graph in the attachment.
