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svetlana [45]
3 years ago
9

Please answer this correctly

Mathematics
2 answers:
Vinil7 [7]3 years ago
7 0

Answer:

V =113.04 cm^3

Step-by-step explanation:

The volume of a cylinder is given by

V = pi r^2 h

V = 3.14 (3)^2 4

V = 3.14 *9*4

V =113.04 cm^3

arlik [135]3 years ago
5 0

Answer:

Step-by-step explanation:

3*3.14

9.42*9.42

88.7364*4

354.9456 rounded to

355

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5/2+18/5+11/4 what is the answer for this question​
Likurg_2 [28]

Answer:

Step-by-step explanation:

basicallyi you want to find a common denominator before you add them up. the common denominator in this case would be 20, since it's the first common multiple all of them share

50/20 plus 72/20 plus 55/20

177/20 would be your answer

3 0
3 years ago
Read 2 more answers
Suppose that the credit remaining on a phone card (in dollars) is a linear function of the total calling time (in minutes). When
Virty [35]

Answer:

Credit remaining after 21 minutes = $30.4

Step-by-step explanation:

Credit remaining on a phone card is a linear function of the total calling time.

When graphed, let the linear function representing the line is,

y = mx + b

Where 'm' = slope of the line

b = y-intercept

From the graph,

Slope of the line = -0.12

y = -0.12x + b

If this line passes through a point (33, 28.96),

28.96 = -0.12(33) + b

b = 28.96 + 3.96

b = 32.92

Therefore, the linear function is,

f(x) = -0.12x + 32.92

where x = calling time

Credit left in the card after 21 minutes,

f(21) = -0.12(21) + 32.92

      = -2.52 + 32.92

      = $30.4

6 0
3 years ago
If you draw four cards at random from a standard deck of 52 cards, what is the probability that all 4 cards have distinct charac
mezya [45]

There are \binom{52}4 ways of drawing a 4-card hand, where

\dbinom nk = \dfrac{n!}{k!(n-k)!}

is the so-called binomial coefficient.

There are 13 different card values, of which we want the hand to represent 4 values, so there are \binom{13}4 ways of meeting this requirement.

For each card value, there are 4 choices of suit, of which we only pick 1, so there are \binom41 ways of picking a card of any given value. We draw 4 cards from the deck, so there are \binom41^4 possible hands in which each card has a different value.

Then there are \binom{13}4 \binom41^4 total hands in which all 4 cards have distinct values, and the probability of drawing such a hand is

\dfrac{\dbinom{13}4 \dbinom41^4}{\dbinom{52}4} = \boxed{\dfrac{2816}{4165}} \approx 0.6761

4 0
2 years ago
Javier volunteers in community events each month. He does not do more than five events in a month. He attends exactly five event
mezya [45]

Answer:

The probability of Javier volunteers for less than three a month is 25%

Step-by-step explanation:

According to the questions,

The probability of Javier to attend exactly 5 events :-

P ( x = 5 ) = 25% = \frac{1}{4}

The probability of Javier to attend exactly 4 events :-

P ( x = 4 ) = \frac{1}{4}

The probability of Javier to attend exactly 3 events :-

P ( x = 3 ) = \frac{1}{4}

The probability of Javier to attend exactly 2 events :-

P ( x = 2 ) = \frac{3}{20}

The probability of Javier to attend exactly 1 events :-

P ( x = 1 ) = \frac{1}{20}

The probability of Javier to attend no events :-

P ( x = 0 ) = \frac{1}{20}

Now we have to calculate the probability of Javier volunteers for less than three P ( x < 3 ).

P ( x < 3 ) = P ( x = 0 ) + P ( x = 1 ) + P ( x = 2 )

P ( x < 3 ) = \frac{1}{20} + \frac{1}{20} + \frac{3}{20}   = \frac{1 + 1 + 3}{20}  = \frac{5}{20}  = \frac{1}{4}   = 0.25 = 25 %.

8 0
3 years ago
A number has the digits 2, 5, and 4 to the nearest 100, the number rounds to 200 what is the number
trapecia [35]

Answer:

245

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
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