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2 years ago

What is the equation of the line graphed below?

Mathematics

2 answers:

agasfer [191]2 years ago

8 0

Answer:

y = 3x - 2

Step-by-step explanation:

(1,1) and (2,4)

Slope = (4 - 1)/(2-1) = 3, y- intercept b = -2

Equation

y = 3x - 2

FromTheMoon [43]2 years ago

8 0

Answer:

Y = 3x - 2 will be the answer.

Step-by-step explanation:

A line has been graphed in the figure attached.

It passes through two points ( 1,1) and (2,4)

Y-intercept of the given line is (-2)

Since equation of a line in the intercept form is

y = mx + c

where m = slope and c = y-intercept

and slope m = $\frac{y-y'}{x-x'}$

Therefore, slope m = $\frac{4-1}{2-1}$

= $\frac{3}{1}$

Therefore, equation of the given line will be y = 3x - 2

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What is (5^-9×5^-2 ÷ 5^-13)^ |7-9| × (5^3 × 5^-5) = ???????

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The answer is: " 5⁻ ⁵⁰ " .
__________________________________________
Note that: |7-9| = <span>| -2 | = 2 .
__________________________________________
Note: 5</span>³ * 5⁻⁵ = 5⁽ ⁽³⁾ ⁺ ⁽⁻⁵⁾ ⁾ = 5⁽³ ⁻ ⁵⁾ = 5⁻² ;
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Note: (5⁻⁹ * 5⁻² ÷ 5⁻¹³) = (5⁻⁹ * 5⁻²) ÷ 5⁻¹³ ;

→ (5⁻⁹ * 5⁻²) = 5⁽⁻⁹⁾ ⁺ ⁽⁻²⁾ = 5 ⁽⁻⁹ ⁻ ²⁾ = 5 ⁻¹¹ ;

→5 ⁻¹¹ ÷ 5⁻¹³ = 5 ⁽⁻¹¹⁾ ⁺ ⁽⁻¹³⁾ = 5⁽⁻¹¹ ⁻ ¹³⁾ = 5⁽⁻²⁴⁾
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→ [ 5⁽⁻²⁴⁾ ] ² = 5⁽⁻²⁴ * ²⁾ = 5⁽⁻⁴⁸⁾ ;
_______________________________________________
Now, rewrite the entire problem; and solve:

→ 5⁽⁻⁴⁸⁾ * 5⁻² = 5⁽⁻⁴⁸⁾ ⁺ ⁽⁻²⁾ = 5⁽⁻⁴⁸⁻²⁾ ;

= 5⁻ ⁵⁰ .
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