3 years ago

Find the least number which exactly divides 35,56 and 91 leaving reminder 7 in each case

2 answers:

3 0

Answer:

The smallest number that when divided by 35;56;91leaves a remainder 7 in each cases 3640+7 equals to 3647. HERE YOUR ANSWER

Kryger [21]3 years ago

3 0

Step-by-step explanation:

then smallest number divided by 35,56 and 91 leaves a remainder 7 in each cases 3640+7 equals to 3647 . here is your answer

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