2 years ago

Find the least number which exactly divides 35,56 and 91 leaving reminder 7 in each case

2 answers:

3 0

Answer:

The smallest number that when divided by 35;56;91leaves a remainder 7 in each cases 3640+7 equals to 3647. HERE YOUR ANSWER

3 0

Step-by-step explanation:

then smallest number divided by 35,56 and 91 leaves a remainder 7 in each cases 3640+7 equals to 3647 . here is your answer

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1000 ml costs £3.50
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Dominik [7]

The correct answer is:

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timurjin [86]

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2 years ago

mr Goodwill [35]

Answer: $x = \pm2\sqrt{7}\\\\$

Work Shown:

$x^2 = 28\\\\x = \pm\sqrt{28}\\\\x = \pm\sqrt{4*7}\\\\x = \pm\sqrt{4}*\sqrt{7}\\\\x = \pm2\sqrt{7}\\\\$

This can be rewritten into $x = 2\sqrt{7} \ \text{ or } \ x = -2\sqrt{7}$

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2 years ago

Len [333]

Answer:

The denominators of 3 /10 and 1 /4 are 10 and 4.

The factors of 10 are 2 × 5 and 2 × 2

Therfore the LCD should have two 2's and one 5.

This means the answer is:

2 × 2 × 5 = <u>20</u>

I hope this helps :)

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3 years ago